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3 years ago

A scale drawing of a rectangular

Mathematics

1 answer:

harkovskaia [24]3 years ago

6 0

Answer:

39 square feet

Step-by-step explanation:

P = 2( L + W)

actual length = 4 * 3 = 12

actual width = 2.5 * 3 = 7.5

P = 2 (12 + 7.5)

P = 2 ( 19.5)

P = 39 feet

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Eden has a part time job. She gets paid £7. 20 per hourthis week she worked for 18 1/2 hourswork out Eden's total pay for this w

Dafna1 [17]

Answer:

$133.20

Step-by-step explanation:

Since the amount of hours she worked isn't a whole number, we can first separate 18 and 1/2 and work the problem out one at a time.

1. Multiply 7.20 by 18 to get 129.60

2. Multiply 0.50 by 7.20 to get 3.60.

3. Add 129.60 and 3.60 together to get the answer, 133.20.

5 0

2 years ago

You want $5000 4 years from nowfor a down payment for a car. How much money must be deposited monetly into an account earning 4.

timama [110]

Answer:

$95.5090 must be deposited monthly

Step-by-step explanation:

From the information given:

The annual interest rate (r) = 4.2% = 0.042

Let assume that an amount Y is deposited, then after one month, it will increase to:

$Y ( 1+ \dfrac{0.042}{12})$

The total amount after 4 years will be:

$= Y ( 1+ \dfrac{0.042}{12})^{48}+Y ( 1+ \dfrac{0.042}{12})^{47} +Y ( 1+ \dfrac{0.042}{12})^{46} +...+ Y ( 1+ \dfrac{0.042}{12})$

$= Y ( 1.0035)^{48}+Y ( 1.0035)^{47} +Y( 1.0035)^{46} +...+ Y( 1.0035)$

Using the sum of a geometric progression:

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{(1.0035-1)}$

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035}$

The above amount is then equal to $5000

i.e

$= Y (1.0035) \dfrac{ (1.0035^{48}-1)}{0.0035} = 5000$

$Y = \dfrac{5000\times 0.0035}{(1.0035)(1.0035^{48}-1)} \\ \\ \mathbf{Y = \$95.5090}$

8 0

3 years ago

The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge

Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

$5x+4y+5z=-1$

$x+y+2z=1$

$2x+y-z=-3$

Firs we find determinant of system of equations

Let a matrix A= $\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right]$ and B= $\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]$

$\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}$

$\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0$

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply $R_1\rightarrow R_1-4R_2$ and $R_3\rightarrow R_3-2R_2$

$\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]$

Apply $R_2\rightarrow R_2-R_1$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]$

Apply $R_3\rightarrow R_3+R_2$

$\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]$

Apply $R_3\rightarrow- \frac{1}{2}$ and $R_2\rightarrow R_2-R_3$

$\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Apply $R_1\rightarrow R_1-R_3$

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$ : $\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]$

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0

3 years ago

Please help ASAP :ppppp

Morgarella [4.7K]

Answer:

I think it's c

Step-by-step explanation:

6 0

3 years ago

What is the value of X? (20 points)

Vitek1552 [10]

Answer:

54.5

Step-by-step explanation:

$x \degree = \frac{1}{2} (160 \degree - 51 \degree) \\ \\ x \degree = \frac{1}{2} \times 109 \degree \\ \\ x \degree = 54.5 \\ \\ x = 54.5$

5 0

3 years ago