Answer:
No solutions.
Step-by-step explanation:
5x = 8x^-1/3
Divide 8 into both sides.
5/8x = x^-1/3
Divide both sides by x.
5/8 = x^-4/3
Multiply both sides by the exponent -3/4.
5/8^-3/4 = x
1.422624 = x
Plug in 1.422624 for x to check.
It does not work. There are no real solutions.
The answer to the question is D.
3,2 was your first point and it dropped to -5,0.
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now,
We know that the sum of probability of an event and its complement is 1.
So,
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
This is a quadratic so if you want to find the solutions, use the quadratic formula. Google quadratic formula and videos on it and how to use it will pop up.
Answer:
The smallest integer is -27 and the integers are -27, -26, and -25
Step-by-step explanation:
We can represent this with:
x + x - 1 + x - 2 = -78
Simplify.
3x - 3 = -78
Add 3 to both sides.
3x = -75
Divide both sides by 3.
x = -25
So, the first integer is -25.
Subtract two to get the smallest integer.
-25 - 2 = - 27