Answer:
I think 155 is a answer and thanks for point
Answer:
I put a pic, i hope ill help :)
Answer:
A sample of 997 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
The margin of error is of:

A previous study indicates that the proportion of left-handed golfers is 8%.
This means that 
98% confidence level
So
, z is the value of Z that has a p-value of
, so
.
How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?
This is n for which M = 0.02. So






Rounding up:
A sample of 997 is needed.
Answer:
X probability = 0.02
Cumulative frequency at x ( 6 ) = 1
Step-by-step explanation:
X P ( X ) Cf ( X )
1 0.58 0.58
2 0.18 0.58 + 0.18 = 0.76
3 0.10 0.76 + 0.10 = 0.86
4 0.07 0.86 + 0.07 = 0.93
5 0.05 0.93 + 0.05 = 0.98
6 0.02 0.98 + 0.02 = 1