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Andru [333]
2 years ago
6

A closed weather balloon with an initial volume V rises up in the atmosphere to a point where the outside air pressure is 1/10 o

f the pressure at sea level and the temperature of the air has dropped by a factor of 3. Assume that the balloon is filled with an ideal gas and that the material of the balloon exerts no pressure and does not insulate so that the temperature and pressure are the same inside and outside the balloon. Do the volume and internal energy of the gas increase, decrease, or stay the same as the balloon rises? Justify your answer.
Physics
1 answer:
Elina [12.6K]2 years ago
5 0

Answer:

PV = nRT

Explanation:

the balloon is closed so n is constant

R is constant

If the temperature was constant, a tenfold decrease in pressure would cause a tenfold increase in volume

If the pressure was constant, a threefold decrease in temperature would result in a threefold decrease in volume.

In this situation, the pressure change overwhelms the temperature change so the volume and internal energy both increase

You might be interested in
- In Einstein's famous equation E = me?, describing the
mel-nik [20]

Answer:

option C is correct

Explanation:

8 0
4 years ago
A runner traveling with an initial velocity of 1.1 m/s accelerates at a constant rate of 0.8 m/s2fora time of 2.0 s.(a).What is
pychu [463]

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

v = u + at

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

7 0
3 years ago
which part of the microscope will be used first to adjust the focus when starting with the lowest power lens?
noname [10]

The first part of the microscope that should first be used to adjust the focus when starting with the lowest power lens would be the coarse adjustment knob.

There are two knobs in a typical light microscope with which objects on slides can be brought into focus:

  1. Coarse adjustment knob
  2. Fine adjustment knob

The 2 knobs are used to adjust the stage to either bring it up towards the objective lens or down away from them. The coarse adjustment knob, however, moves the stage a considerable distance with each turn. The fine adjustment knob, on the other hand, only moves the stage very little with each turn.

The lowest power lenses are often short. Hence, using the coarse adjustment knob is ideal in order to quickly bring objects on slides into focus.

The fine adjustment knob comes highly recommended at high objectives because high objectives lenses are usually long and using the coarse adjustment knob can lead to a breakage of the slide by the lens.

More on bringing objects into focus on a microscope can be found here: brainly.com/question/24319677

7 0
3 years ago
The muzzle velocity of a rifle bullet is 800. m⋅ s −1 m⋅s−1 along the direction of motion. If the bullet weighs 27.0 g g , and t
11Alexandr11 [23.1K]

Answer:

1.98 × 10⁻³³m

Explanation:

It is given that,

Mass of the bullet, m = 27 g = 0.027 kg

Velocity of bullet, v = 800 m/s

The uncertainty in momentum is 0.20%. The momentum of the bullet is given by :

p=mvp=0.027\times 800 = 21.6\ kg-m/s

Uncertainty in momentum is,

\Delta p=0.2\%\ of\  21.6\\\Delta p=0.0432

We need to find the uncertainty in position. It can be calculated using Heisenberg uncertainty principal as :

\Delta p.\Delta x\geq \dfrac{h}{4\pi}\Delta x=\dfrac{h}{4\pi \Delta p}\Delta x=\dfrac{6.62\times 10^{-34}}{4\pi \times 0.0432}\Delta x=1.98\times 10^{-33}\ m

4 0
4 years ago
When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st
defon

Answer:

Current in the hair dryer will be equal to 15 A

Explanation:

We have given that household is operated at 110 volt

So potential difference V =110 volt

Power drawn by hairdryer is P = 1650 watt

We have to find the current in the hair dryer

We know that power is given as P = VI, here V is potential difference and I is current

So 1650=110\times I

I = 15 A

So current in the hair dryer will be equal to 15 A

4 0
4 years ago
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