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Mrrafil [7]
3 years ago
7

During nuclear decay, a new isotope is created. How is the nucleus of the new isotope different from the parent if the parent is

otope has undergone alpha decay?
Physics
2 answers:
Veseljchak [2.6K]3 years ago
6 0

Answer:

the difference in parent nuclei and daughter nuclei is that daughter nuclei is having smaller mass number and by 4 and smaller atomic number by 2

_z^AX ----> _{z-2}^{A-4}Y + _2^4He

Explanation:

Alpha nucleus is the helium nuclei which is having 2 protons and 2 neutrons

So we will have

\alpha = _2^4He

now we know that in all radioactive decay mass number and atomic number will remain constant on product and reactant side

So we have

X ------> Y + \alpha

now by mass number conservation and atomic number conservation we have

_z^AX ----> _{z-2}^{A-4}Y + _2^4He

so the difference in parent nuclei and daughter nuclei is that daughter nuclei is having smaller mass number and by 4 and smaller atomic number by 2

STALIN [3.7K]3 years ago
3 0

Answer:

Alpha decay will produce a daughter nucleus with more protons and beta decay will produce a daughter nucleus with fewer protons than the parent nucleus has.

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Answer:

★The second law of refraction

The ratio of sine of angle of incidence to the sine of angle of refraction is a constant for a light of given colour and for a given pair of media. This law is also called Snell's law of refraction. If 'i' is the angle of incidence and 'r' is the angle of refraction then, Sin i/Sin r = constant

This constant value is called the refractive index of the second medium with respect to the first.

7 0
3 years ago
If planet i is 30.3 million miles farther from the sun than planet​ ii, then planet iii is 24.6 million miles farther from the s
kkurt [141]
Since the total distance for all three of the planets is 196.2 million miles, you would add planet i and planet iii, then subtract that number from 196.2

planet i and planet iii equaled 54.9 million miles, that subtracted from 196.2 equals 141.3

So your answer is 141.3 million miles
3 0
3 years ago
A Nerf gun is shot straight up from the ground with an initial velocity of 14.0 m/s. What is the total time the projectile is in
Sergeeva-Olga [200]

The projectile has a height <em>h</em> at time <em>t</em> given by

<em>h</em> = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for <em>t</em> when <em>h</em> = 0 :

0 = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²

0 = 1/2 <em>t</em> (28.0 m/s - <em>g t</em> )

1/2 <em>t</em> = 0   <u>or</u>   28.0 m/s - <em>g</em> <em>t</em> = 0

The first equation says <em>t</em> = 0, which refers to the moment the gun is first fired, so we ignore that solution. We're left with

28.0 m/s - <em>g t</em> = 0

<em>t</em> = (28.0 m/s) / <em>g</em>

<em>t</em> = (28.0 m/s) / (9.80 m/s²)

<em>t</em> ≈ 2.86 s

7 0
3 years ago
A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
Law Incorporation [45]

Answer:

y and length is directly relation

Explanation:

Given data

A single-slit diffraction pattern is formed on a distant scree

angles involved = small

to find out

what factor will the width of the central bright spot on the screen change

solution

we know that  for single slit screen formula is

mass ƛ /area = sin θ and y/L = sinθ

so we can say mass ƛ /area =  y/L

and y = mass length  ƛ / area       .................1

in equation 1 here we can see y and length is directly relation so we can say from equation 1 that  the width of the central bright spot on the screen change if the distance from the slit to the screen is doubled

8 0
3 years ago
What is the mass of an object that weighs 686N on Earth?
madreJ [45]

Answer:

70 kg

Explanation:

F=m•a

m=F/a

m= 686/9,8= 70kg

4 0
4 years ago
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