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Mrrafil [7]
3 years ago
7

During nuclear decay, a new isotope is created. How is the nucleus of the new isotope different from the parent if the parent is

otope has undergone alpha decay?
Physics
2 answers:
Veseljchak [2.6K]3 years ago
6 0

Answer:

the difference in parent nuclei and daughter nuclei is that daughter nuclei is having smaller mass number and by 4 and smaller atomic number by 2

_z^AX ----> _{z-2}^{A-4}Y + _2^4He

Explanation:

Alpha nucleus is the helium nuclei which is having 2 protons and 2 neutrons

So we will have

\alpha = _2^4He

now we know that in all radioactive decay mass number and atomic number will remain constant on product and reactant side

So we have

X ------> Y + \alpha

now by mass number conservation and atomic number conservation we have

_z^AX ----> _{z-2}^{A-4}Y + _2^4He

so the difference in parent nuclei and daughter nuclei is that daughter nuclei is having smaller mass number and by 4 and smaller atomic number by 2

STALIN [3.7K]3 years ago
3 0

Answer:

Alpha decay will produce a daughter nucleus with more protons and beta decay will produce a daughter nucleus with fewer protons than the parent nucleus has.

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A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
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Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

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Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

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When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

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When the gymnast climbs up the rope with an upward acceleration of magnitude

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the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
3 years ago
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Answer:

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