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Rama09 [41]
3 years ago
6

Write a balanced equation for the formation of co2 g from c s and o2 g

Chemistry
1 answer:
devlian [24]3 years ago
6 0

Answer:

C (s) + O2 (g) > CO2 (g)

That's what I got

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A reaction occurs in which hydrogen-1 and hydrogen-2 form helium-3. Is this a chemical reaction or a nuclear reaction, and how d
olga nikolaevna [1]
Cause -3 is -3sjsnsnsnsnsnnsnsnsnnsnsnsnsn
7 0
3 years ago
Compound name for C3F8
Naya [18.7K]

Answer:

Perflutren

Explanation:

Perflutren is a fluorinated hydrocarbon and gaseous substance used as an imaging contrast agent.

8 0
3 years ago
Select the correct answer.
ivann1987 [24]

Answer:

C.

Explanation:

The electronic configuration of N (7 electrons): 1s² 2s² 2p³.

The orbital 1s is filled with two electrons and their spinning direction is opposite and also electrons of 2s.

3p contains (3 electrons) should fill the 3 orbitals firstly. Every orbital contains 1 electron and be in the same spin direction.

So, the right choice is c.

A is wrong because 2 electrons of 3p are paired in the first orbital before filling every orbital.

B is wrong because the 2 electrons of 1s and 2s are in the same direction and also 2 electrons of 3p are paired in the first orbital before filling every orbital.

D is also wrong the 2 electrons of 1s and 2s are in the same direction and the electron in the second orbital of 3p are in opposite direction of the other 2 electrons.

7 0
4 years ago
According to the law of conservation of mass, the total mass of the reacting substances is
atroni [7]

Answer:

I would say the last one because mass is not created nor destroyed.

Explanation:

7 0
3 years ago
16.0 grams of molecular oxygen gas is equal to
IceJOKER [234]

One thing to notice in the question is, we are asked about molecular oxygen that has formula O2 not atomic oxygen O.

As we are asked about molecular oxygen, we will answer the question in terms of number of molecules that are present in 16 grams of molecular oxygen.

To get the number of molecules present in 16 grams of O2, we will use the formula:

         No. of molecules = no. of moles x Avogadro's number (NA)-----  eq 1)

As we know:

                        The number of moles = mass/ molar mass of molecule

Here we have been given mass already, 16 grams and the molar mass of O2 is 32 grams.

Putting the values in above formula:

                                                    = 16/32  

                                                     = 0.5 moles

Putting the number of moles and Avogadro's number (6.02 * 10^23) in eq 1

                                No. of molecules = 0.5  x 6.02 * 10^23

                                   =3.01 x 10^23 molecules

or                 301,000,000,000,000,000,000,000 molecules

This means that 16 grams of 3.01 x 10^23 molecules of oxygen.

Hope it helps!

4 0
4 years ago
Read 2 more answers
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