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grin007 [14]
2 years ago
14

I need serious help with solving this problem.

Chemistry
1 answer:
Damm [24]2 years ago
6 0

The final molarity of this diluted solution is equal to 6.0 M.

<u>Given the following data:</u>

  • Initial volume = 4.0 mL
  • Initial molarity = 12.2 M
  • Final volume = 8.0 mL

To calculate the final molarity of this diluted solution:

<h3>The formula for the molarity of a solution.</h3>

Mathematically, the relationship between the molarity of a solution and volume is given by the formula:

MV = k\\\\M_1V_1 = M_2V_2

<u>Where:</u>

  • M is the molarity of a solution.
  • V is the volume of a solution.

Making M_2 the subject of formula, we have:

M_2 = \frac{M_1V_1}{V_2}

Substituting the given parameters into the formula, we have;

M_2 = \frac{12 \times 4.0}{8.0} \\\\M_2 = \frac{48}{8.0}

Final molarity = 6.0 M

Read more on molarity here: brainly.com/question/17138838

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Explanation:

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Since only solvent is added, the amount of the solute, NaOH, in the dilute solution is the same as in the volume taken from the stock solution.

Molarity (<em>M)</em> is calculated from the following equation:

<em>M</em> = <em>n</em> ÷ <em>V</em>

where <em>n</em> is the number of moles of the solute in the solution, and <em>V</em> is the volume of the solution.

Accordingly, the number of moles of the solute is given by

<em>n</em> = <em>M</em> x <em>V</em>

Now, let's designate the stock NaOH solution and the dilute solution as (1) and (2), respectively . The number of moles of NaOH in each of these solutions is:

<em>n </em>(1) = <em>M </em>(1) x <em>V </em>(1)

<em>n </em>(2) = <em>M </em>(2) x <em>V </em>(2)

As the amount of NaOH in the dilute solution is the same as in the volume taken from the stock solution,

<em>n</em> (1) = <em>n</em> (2)

and

<em>M</em> (1) x <em>V</em> (1)<em> </em>= <em>M</em> (2) x <em>V</em> (2)

For the stock solution, <em>M</em> (1) = 1.244 M, and <em>V</em> (1) is the volume needed. For the dilute solution, <em>M</em> (2) = 0,1281 M, and <em>V</em> (2) = 250.0 mL.

The volume of the stock solution needed, <em>V</em> (1), is calculated as follows:

<em>V</em> (1) = <em>M</em> (2) x <em>V</em> (2) ÷ <em>M</em> (1)

<em>V</em> (1) = 0.1281 M x 250.0 mL ÷ 1.224 M

<em>V </em>(1) = 26.16 mL

The volume of the 1.224 M NaOH solution needed is 26.16 mL.

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