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Deffense [45]
3 years ago
8

Glaciers are agents of deposition and erosion. When we talk about glacial erosion, we consider both the erosion processes and th

e
erosion features. There are two main processes of glacial erosion. What are they?
A)abrasion and plucking

B)dissolving and melting
striations and scratching

C)striations and scratching

D)terminal moraine and outwash plain
Chemistry
1 answer:
const2013 [10]3 years ago
7 0
I think it is B

Explained answer:
Glaciers dissolve and melt because they are made out of ice
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300 moles of sodium nitrite are needed for a reaction. the solution is 0.450 m. how many ml are needed?
miv72 [106K]

Answer:

\boxed{\text{667 000 mL}}

Explanation:

\text{Molar concentration} = \dfrac{\text{moles}}{\text{litres}}\\\\c = \dfrac{n}{v}

Data:

c = 0.450 mol·L⁻¹

n = 300 mol

Calculation:

\begin{array}{rcl}0.450 & = & \dfrac{300}{V}\\\\0.450V& = & 300\\\\V & = & \dfrac{300}{0.450}\\\\V & = & \text{667 L} =\textbf{667 000 mL}\end{array}\\\text{The volume of solution needed is }\boxed{\textbf{667 000 mL}}

4 0
3 years ago
Removing one electron from an atom results in the formation of an Question 7 options: ion with a 1- charge. ion with a 7+ charge
olga nikolaevna [1]

I believe it is an ion with a 1+ charge. If you remove an electron from an atom it will have a positive charge. But if you add electrons it will be a negative charge. Hope I helped!

5 0
3 years ago
Describe how you would crystallise potassium nitrate from its aqueous liquid?
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3 years ago
Whats two answers I know B is wrong
JulijaS [17]

Answer:A and D

Explanation:

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3 years ago
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Food dye allergies have increased in recent years. One study calculated that each 47.9 g serving of M&M's candy contains 240
77julia77 [94]

Answer:

Mass percent of food dyes  = 0.0616%

Explanation:

Given data:

Mass of candy = 47.9 g

Calories = 240

Mass of fat = 10 g

Mass of carbohydrate = 34 g

Mass of protein = 2 g

Mass of food dyes = 29.5 mg

Mass percent of food dyes = ?

Solution:

First of all we will convert the mg into g.

Mass of food dyes = 29.5 mg × 1g /1000 mg = 0.0295 g

Mass percent of food dyes  = mass of food dyes / total mass× 100

Now we will put the values.

Mass percent of food dyes  = 0.0295 g / 47.9 g × 100

Mass percent of food dyes  =  0.000616 × 100

Mass percent of food dyes  = 0.0616%

3 0
3 years ago
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