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Deffense [45]
3 years ago
8

Glaciers are agents of deposition and erosion. When we talk about glacial erosion, we consider both the erosion processes and th

e
erosion features. There are two main processes of glacial erosion. What are they?
A)abrasion and plucking

B)dissolving and melting
striations and scratching

C)striations and scratching

D)terminal moraine and outwash plain
Chemistry
1 answer:
const2013 [10]3 years ago
7 0
I think it is B

Explained answer:
Glaciers dissolve and melt because they are made out of ice
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What is the percent composition of Br in CuBr3?
tekilochka [14]

Answer:

about 79% (79.04369332 to be exact)

Explanation:

Percent composition=(Molar mass of element x amount of it)/Molar mass of compound x 100

Br= 3 x 79.9/303.25 x100=79.04369332

6 0
3 years ago
How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
3 years ago
Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest
balu736 [363]

Answer:

Cost to supply enough vanillin is 3.2\$

Explanation:

Threshold limit of vanillin in air is 2.0\times 10^{-11}g per litre means there should be 2.0\times 10^{-11}g of vanillin in 1L of air to detect aroma of vanillin.

1ft^{3}=28.32L

So, 5.0\times 10^{7}ft^{3}=(5.0\times 10^{7}\times 28.32)L

So amount of vanillin should be present to detect = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)g

As cost of 50 g vanillin is 112\$ therefore cost of  (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32)gvanillin = (2.0\times 10^{-11}\times 5.0\times 10^{7}\times 28.32\times 112)\$ = 3.2\$

5 0
3 years ago
Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight
Salsk061 [2.6K]

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒  Mass \ of \ Butane = Density\times Volume

On putting the estimated values, we get

⇒                              =0.579\times 7.96

⇒                              =4.60 \ g

6 0
3 years ago
Which of these hypotheses cannot be tested?
SVEN [57.7K]

Cooks should use sea salt in recipes instead of regular table salt.

7 0
3 years ago
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