412 kelvin = 138.85° celsius
Answer:
Unit of power is watt
Explanation:
Power = rate of doing work
or
Power, P = W/t
Where
W is work done and t is time
The unit of work done is Joules and that of time is seconds.
Power, P = J/s
We know that, J/s = watts
Hence, the unit of power is watts.
1) Balanced chemical equation
8H2S +4O2 ---> S8 + 8H2O
2) Molar ratios
8 mol H2S : 4 mol O2 : 1 mol S8
3) Convert 50.0 grams of H2S into moles
moles = mass in grams / molar mass
molar mass H2S = 2*1g/mol + 32.1 g/mol = 34.1 g/mol
moles = 50.0 g / 34.1 g/mol = 1.466 moles H2S
4) Convert 60.0 g of O2 into moles
molar mass O2 = 2*16g/mol = 32.0g/mol
moles = 60.0g / 32.0 g = 1.875 moles O2
5) State limiting reagent
Theoretical ratio: 8 mol H2S / 4 mol O2 = 8/4 = 2/1 = 2
Actual ratio 1.466 mol H2S / 1.875 mol O2 < 2
=> H2S is the limiting reagent (it is consumed completely whilce some O2 remains unreacted).
6) Determine the moles of S8 produced from 1.466 moles H2S
1 mol S8 / 8 mol H2S * 1.466 mol H2S = 0.18325 mol S8
7) Convert 0.18325 mol S8 to mass
mass = number of moles * molar mass
molar mass S8 = 8 mol * 32.1g/mol = 256.8 g/mol
mass = 0.18325 mol * 256.8 g/mol = 47.1 grams
Answer: 47.1 g
Answer:
See explanation
Explanation:
Polymerization refers to the formation of a macro-molecule by the aggregation of small molecules called monomers. Monomers are the small molecules that are joined together to form a polymer.
The formation of a condensation polymer is accompanied by the loss of a small molecules such as water as shown in the image attached.
Succinic acid reacts with ethylenediamine to form a nylon type polymer. The nature of this reaction is detailed in the image attached to this answer. Recall that a polymer may contain (n) number of monomers joined together in the macromolecule.
Answer:
a. There are only 5 electrons in 2p. 2p should be filled with 6 electrons prior to 3s and 3p
b. There are 8 electrons in 2p. 2p should be filled only with 6 electrons (not 8)
Explanation:
The typical electron configuration: 1s2 2s2 2p6 3s2 3p6
a. There are only 5 electrons in 2p
=> should be 1s2 2s2 2p6 3s2 3p2
b. There are 8 electrons in 2p
=> should be 1s2 2s2 2p6 3s2 3p1