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algol [13]
3 years ago
13

The minimum amount of 100-degree-c steam needed to melt 1 gram of 0-degree-celsius ice is

Chemistry
1 answer:
kvv77 [185]3 years ago
7 0
The mass of ice to be melted is
1 g = 10⁻³ kg.

Let m =  the mass of steam required to melt the ice.

For water,
The latent heat of vaporization is 2260 kJ/kg
The latent heat of fusion is 334 kJ/kg

The steam should give up its latent heat of vaporization to melt the ice, which gives up its latent heat of fusion.
Therefore
(m kg)*(2260 kJ/kg) = (10⁻³ kg)*(334 kJ/kg)
m = 1.478 x 10⁻⁴ kg = 0.1478 g

Answer: 0.148 g

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The total pressure in a mixture of gases is equal to the partial pressures of
baherus [9]

Answer:

"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

Explanation:

Dalton's law of partial pressures state that, in a mixture of gases, the total pressure is equal to the sum of the partial pressure exerted by each gas of the mixture. The equation is:

Total pressure = Partial pressure Gas 1 + Partial pressure Gas 2 + .... + Partial pressure Gas n

To complete the sentence we can say:

"The total pressure in a mixture of gases is equal to the sum of partial pressures of each gas"

5 0
2 years ago
An unknown gas Q requires 2.67 times as long to effuse under the same conditions as the same amount of nitrogen gas. What is the
Misha Larkins [42]

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

3 0
3 years ago
What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15°C?
Oksanka [162]
The specific heat capacity  the substance is calculated  using  the below formula

Q(heat) = Mc delta T
Q =1560  cal
m(mass) 312 g
delta T (change in temperature ) = 15 c
C= specific heat capacity=?

by making c the subject of the formula 
c=Q/m delta T
= 1560  cal/ 312g x 15 c = 0.33 cal/g/c (answer B)


8 0
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The following animals is an endotherm? A. grasshopper B.horse C.lizard D.snake
adoni [48]

Answer:

snake

Explanation:

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