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4 years ago

The minimum amount of 100-degree-c steam needed to melt 1 gram of 0-degree-celsius ice is

1 answer:

7 0

The mass of ice to be melted is
1 g = 10⁻³ kg.

Let m = the mass of steam required to melt the ice.

For water,
The latent heat of vaporization is 2260 kJ/kg
The latent heat of fusion is 334 kJ/kg

The steam should give up its latent heat of vaporization to melt the ice, which gives up its latent heat of fusion.
Therefore
(m kg)*(2260 kJ/kg) = (10⁻³ kg)*(334 kJ/kg)
m = 1.478 x 10⁻⁴ kg = 0.1478 g

Answer: 0.148 g

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The charge on a sulfide ion is

Fudgin [204]

Answer: The charge on a sulfide ion is –2.

Explanation:

6 0

3 years ago

Butane C4H10 (g),(Hf = –125.7), combusts in the presence of oxygen to form CO2 (g) (Delta.Hf = –393.5 kJ/mol), and H2O(g) (Delta

shusha [124]

Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ

Explanation:

The balanced chemical reaction is,

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]$

Putting the values we get :

$\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]$

$\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]$

$\Delta H=-5314.8kJ$

2 moles of butane releases heat = 5314.8 kJ

1 mole of butane release heat = $\frac{5314.8}{2}\times 1=2657.4kJ$

Thus enthalpy of combustion per mole of butane is -2657.4 kJ

3 0

3 years ago

What structure would you only find in plant cells?

KengaRu [80]

Answer:

vacuole, cell wall, and plastids such as chloroplasts.

Explanation:

hope this helps u

8 0

3 years ago

Read 2 more answers

Lynne is riding her bike at a speed of 22.55<br> km/hr. What is this speed in mi/min?

antiseptic1488 [7]

Answer:

0.2335320064 mi/min

Explanation:

1 km/h = 0.0103561865 mi/min

1 mi/min = 96.56064 km/h

For conversion:

22.55 km/hr = 22.55 x 0.0103561865 mi/min = 0.2335320064 mi/min

6 0

2 years ago

How many more neutrons would be in an isotope of sulfur-31 than a normal sulfur atom?

telo118 [61]

As sulfur-31 has 16 protons (equivalent to the atomic number) in total. The quantity of protons and electrons in an atom is equal. Consequently, sulfur-31 has 16 electrons in total.

As a result, sulfur-31 has (31-16) or 15 neutrons (the difference between the mass number and atomic number).

What is the atomic number?

The average mass of an element's atoms expressed in atomic mass units is known as its atomic mass (amu, also known as daltons, D).

The mass of each isotope is multiplied by its abundance to produce the atomic mass, which is a weighted average of all the isotopes of that element.
(Atomic mass is also known as atomic weight however, "mass" is a more precise phrase.)

The atomic mass of an element, measured in AMU, is equal to the mass in grams of one mole of an element.

This relationship between the atomic mass and the mole concept is important in chemistry.

Hence, the answer is 15neutrons.

Learn more about the atomic numbers,

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8 0

2 years ago