Explanation:
Bernoulli equation for the flow between bottom of the tank and pipe exit point is as follows.
= 
![\frac{(100 \times 144)}{62.43} + 0 + h[tex] = [tex]\frac{(50 \times 144)}{(62.43)} + \frac{(70)^{2}}{2(32.2)} + 0 + 40 + 60](https://tex.z-dn.net/?f=%5Cfrac%7B%28100%20%5Ctimes%20144%29%7D%7B62.43%7D%20%2B%200%20%2B%20h%5Btex%5D%20%3D%20%5Btex%5D%5Cfrac%7B%2850%20%5Ctimes%20144%29%7D%7B%2862.43%29%7D%20%2B%20%5Cfrac%7B%2870%29%5E%7B2%7D%7D%7B2%2832.2%29%7D%20%2B%200%20%2B%2040%20%2B%2060)
h = 
= 60.76 ft
Hence, formula to calculate theoretical power produced by the turbine is as follows.
P = mgh
= 
= 6076 lb.ft/s
= 11.047 hp
Efficiency of the turbine will be as follows.
= 
× 100%
= 
= 52.684%
Thus, we can conclude that the efficiency of the turbine is 52.684%.
Answer:
They are both pretty soft for metals, but magnesium is significantly harder than calcium using this scale . Mg = 2.5, Ca = 1.75. The larger the number, the harder
Explanation:
By decreasing n we can increase presure because decrease in n will shift equilibrium to either forward or reverse direction
The answer to this problem is 11.6m
Answer:
Molar mass→ 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
Explanation:
Let's apply the formula for freezing point depression:
ΔT = Kf . m
ΔT = 74.2°C - 73.4°C → 0.8°C
Difference between the freezing T° of pure solvent and freezing T° of solution
Kf = Cryoscopic constant → 5.5°C/m
So, if we replace in the formula
ΔT = Kf . m → ΔT / Kf = m
0.8°C / 5.5 m/°C = m → 0.0516 mol/kg
These are the moles in 1 kg of solvent so let's find out the moles in our mass of solvent which is 0.125 kg
0.0516 mol/kg . 0.125 kg = 6.45×10⁻³ moles. Now we can determine the molar mass:
Molar mass (mol/kg) → 0.930 g / 6.45×10⁻³ mol = 144.15 g/mol
