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Firlakuza [10]
3 years ago
12

Please help! will mark brainliest

Chemistry
1 answer:
Step2247 [10]3 years ago
3 0

Answer:

add me!!!

Explanation:

my insta is: becomewhatyouwant2inlife

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how can knowledge of percent composition help you as a consumer ? how can you promote responsible consumerism ?​
Nonamiya [84]

Answer:

it is a nice question....my mind tells me that the first is it use me as a good vibes and can use to anything the second i will do my best too absorbe it.

Explanation:

Hope this help...

8 0
3 years ago
A mixture of calcium carbonate, CaCO3, and barium carbonate, BaCO3, weighing 5.40 g reacts fully with hydrochloric acid, HCl(aq)
amid [387]

Answer:

CaCO₃ = 85.18%

BaCO₃ = 14.82%

Explanation:

The acid will react with the salts, the partial reactions are:

CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O

BaCO₃ + 2HCl → BaCl₂ + CO₂ + H₂O

So, the total amount of CaCO₃ BaCO₃ will form the CO₂.

Using the ideal gas law to calculate the number of moles of CO₂:

PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant (0.082 atm*L/mol*K), and T is the temperature (50ºC + 273 = 323 K).

0.904*1.39 = n*0.082*323

26.486n = 1.25656

n = 0.05 mol

So, the number of moles of the mixture is 0.05 mol.

The molar masses of the components are:

CaCO₃ = 40 g/mol of Ca + 12 g/mol of C + 3*16 g/mol of O = 100 g/mol

BaCO₃ = 137.3 g/mol of Ba + 12 g/mol of C + 3*16 g/mol of O = 197.3 g/mol

Let's call x the number of moles of CaCO₃ and y the number of moles of BaCO₃, so:

100x + 197.3y = 5.4

x + y = 0.05 mol

y = 0.05 - x

100x + 197.3*(0.05 - x) = 5.4

100x - 197.3x = 5.4 - 9.865

97.3x = 4.465

x = 0.046 mol of CaCO₃

y = 0.004 mol of BaCO₃

So, the masses are:

CaCO₃ = 100* 0.046 = 4.60 g

BaCO₃ = 137.3*0.004 = 0.80 g

The percentages in the mixture are:

CaCO₃ = (4.60/5.40)*100% = 85.18%

BaCO₃ = (0.80/5.40)*100% = 14.82%

4 0
3 years ago
At stp, a 12.0 liter sample of CH4 has the same total number of molecules as
Elden [556K]

Option 2: 12.0 L of CO_{2} (g) at STP.

The standard pressure and temperature values are 1 atm and 273.15 K.

Using the ideal gas equation, number of moles of gas can be calculated which is as follows:

PV=nRT...... (1)

Here, P is pressure, V is volume, n is number of moles, R is gas constant and T is temperature.

Also, in 1 mole of any gas there are 6.023\times 10^{23} molecules of the gas. This is known as Avogadro's number and denoted by symbol N_{A}

Thus,

N=n\times N_{A}

Equation (1) can be rewritten as follows:

PV=\frac{N}{N_{A}}RT

On rearranging,

N=\frac{P\times V\times N_{A}}{R\times T}

Here, all the other terms are constant except volume, thus, gas with volume equal to the volume of CH_{4} will have same number of molecules.

Volume of CH_{4} gas and CO_{2}gas is same thus, CH_{4} will have same total number of molecules as  CO_{2} gas.


5 0
3 years ago
Read 2 more answers
The following is what type of reaction: A + B → C
galina1969 [7]
Combination reaction
6 0
3 years ago
More active metals will cause the reduction of less active metals. Less active metals will cause no reaction (N.R.) in more acti
beks73 [17]

Activity of metals with most active and less active metals are given below.

Explanation:

1. Activity of metals -Divide metals Based on the activity.

2. The primary difference between metals is the ability with which they undergo chemical reactions. The elements toward the bottom left corner of the periodic table are the metals that are the most active in the sense of being the most reactive. Lithium, sodium, and potassium all react with water, for example. The rate of this reaction increases as we go down this column, however, because these elements become more active as they become more metallic.

3. Common Metals Divided into Classes on the Basis of Their Activity

  • Class I Metals: The Active Metals -Li, Na, K, Rb, Cs (Group IA)  ,Ca, Sr, Ba (Group IIA)
  • Class II Metals: The Less Active Metals -Mg, Al, Zn, Mn
  • Class III Metals: The Structural Metals -Cr, Fe, Sn, Pb, Cu
  • Class IV Metals: The Coinage Metals -Ag, Au, Pt, Hg

4. The most active metals are so reactive that they readily combine with the O2 and H2O vapor in the atmosphere and are therefore stored under an inert liquid, such as mineral oil. These metals are found exclusively in Groups IA and IIA of the periodic table.

5. Metals in the second class are slightly less active. They don't react with water at room temperature, but they react rapidly with acids.

6.The third class contains metals such as chromium, iron, tin, and lead, which react only with strong acids. It also contains even less active metals such as copper, which only dissolves when treated with acids that can oxidize the metal.

7. Metals in the fourth class are so unreactive they are essentially inert at room temperature. These metals are ideal for making jewelry or coins because they do not react with the vast majority of the substances with which they come into daily contact. As a result, they are often called the "coinage metals."

Fe⁺² (aq)+Zn(s)=>Zn⁺² (aq)+Fe(s)

3 0
3 years ago
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