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Nimfa-mama [501]
3 years ago
12

Convert 75.0 degrees Fahrenheit into Celsius

Physics
2 answers:
lesya692 [45]3 years ago
8 0

Answer:

23.889. answer answer answer

nikdorinn [45]3 years ago
3 0

Answer:

23.889 Celcius

Explanation:

(75°F − 32) × 5/9 = 23.889°C

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A motor exerts a 280 N force and does 1220 J
finlep [7]

We know that:

  • Work = Force × Distance

Solving for Distance:

  • Distance = Work / Force
  • Distance = 1220 J / 280 N
<h3>        Distance = 4.36 m </h3>

5 0
3 years ago
The amount of light lost within a fiber-optic system is known as
densk [106]
Attenuation is the correct answer. 
6 0
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When I wave a charged golf tube at the front of the classroom with a frequency of two oscillations per second, I produce an elec
borishaifa [10]

To solve the exercise it is necessary to take into account the concepts of wavelength as a function of speed.

From the definition we know that the wavelength is described under the equation,

\lambda = \frac{c}{f}

Where,

c = Speed of light (vacuum)

f = frequency

Our values are,

f = 2Hz

c = 3*10^8km/s

Replacing we have,

\lambda = \frac{c}{f}

\lambda = \frac{3*10^8km/s}{2Hz}

\lambda = 1.5*10^8m

<em>Therefore the wavelength of this wave is 1.5*10^{8}m</em>

8 0
3 years ago
Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length t
gladu [14]

The question is incomplete. The complete question is :

Assume that the energy lost was entirely due to friction and that the total length of the PVC pipe is 1 meter. Use this length to compute the average force of friction (for this calculation, you may neglect uncertainties).

Mass of the ball :  16.3 g

Predicted range :  0.3503 m

Actual range : 1.09 m

Solution :

Given that :

The predicted range is 0.3503 m

Time of the fall is :

$t=\sqrt{\frac{2H}{g}}$

v_1t= 0.35  ...........(i)

v_0t= 1.09  ...........(ii)

Dividing the equation (ii) by (i)

$\frac{v_0t}{v_1t}=\frac{1.09}{035} = 3.11$

∴ v_0=3.11  \ v_1

Now loss of energy  = change in the kinetic energy

$W=\frac{1}{2} m [v_0^2-v_1^2]$

$W=\frac{1}{2} \times (16.3 \times 10^{-3}) \times [v_0^2-\left(\frac{v_0}{3.11}\right)^2]$

$W=7.307\times 10^{-3} \ v_0^2$

If f is average friction force, then

(f)(L) = W

(f) (1) = $7.307\times 10^{-3} \ v_0^2$

(f)  = $7.307\times 10^{-3} \ v_0^2$

3 0
3 years ago
How big is a wifi pulse signal coming from your router???
Brilliant_brown [7]

Answer:

About 15

Explanation:

7 0
3 years ago
Read 2 more answers
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