Answer:
k = 45.95 N/m
Explanation:
First, we will find the launch speed of the ball by using the formula for the horizontal range of the projectile.

where,
Vo = Launch Speed = ?
R = Horizontal Range = 5.3 m
θ = Launch Angle = 35°
Therefore,

v₀² = 55.33 m²/s²
Now, we know that the kinetic energy gain of ball is equal to the potential energy stored by spring:

where,
k = spring constant = ?
x = compression = 17 cm = 0.17 m
m = mass of ball = 24 g = 0.024 kg
Therefore,

<u>k = 45.95 N/m</u>
The car has an initial velocity
of 23 m/s and a final velocity
of 0 m/s. Recall that for constant acceleration,

The car stops in 7 s, so the acceleration is


Answer:
Yes it is possible
Explanation:
When two equal magnitude forces are acting on the rod in opposite direction
Then the net force on the system is always zero in that case
so we will have

now for the system net torque due to these forces is given by

here we know that
= distance of the forces from reference about which torque is measured
so here we can say that net force is zero on the system while torque is not zero
in all such case object will rotate about a fixed position with change angular speed
There are 3 significant figures, if that answers the question.