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Olenka [21]
2 years ago
5

What is the weight of a 63.7 kg person? ?N

Physics
2 answers:
Ivan2 years ago
6 0

Answer:

140.434 lb is what I got as an answer

viktelen [127]2 years ago
6 0

Answer:

624.26

Explanation:

63.7 kg x 9.8 (force of gravity) = 624.26N

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When an electron is displaced in a semiconductor, the hole that's left behind is
morpeh [17]

Answer:

A. attracted to the negative terminal of the voltage source.

Explanation:

When an electron is displaced in a semiconductor, the hole that's left behind is

A. attracted to the negative terminal of the voltage source.

The electron leaving leaves a net + charge, which is attracted to the negative terminal.

8 0
2 years ago
When air resistance balances the weight of an object that is falling, the velocity _____.
miskamm [114]
Decreases. Air resistance will slow a falling object to its terminal velocity, placing a limit on its acceleration. 
5 0
3 years ago
An automobile moves on a level horizontal road in a circle of radius 30 m. The coefficient of
blondinia [14]

Answer:

v = 12.12 m/s      

Explanation:

It is given that,

Radius of circle, r = 30 m

The coefficient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

5 0
3 years ago
A 9V battery produces a 1.5A current in a piece of wire. What is the resistance of the wire?
MAVERICK [17]

Explanation:

Using Ohm's Law and a bit of substitution, we can use voltage divided by current to solve for resistance. Doing that, we'll get 6 Ohm.

4 0
2 years ago
147.5 ml of ethyl alcohol (coefficient of volume expansion = 1120 x 10-6K-1) at a temperature of 273.1 K is measured into a 150.
marishachu [46]

Answer:

288.2 K

Explanation:

\beta = Volumetric expansion coefficient = 1120\times 10^{-6}\ /K

T_i = Initial temperature = 273.1 K

T_f = Final temperature

v_0 = Original volume = 150 mL

Change in volume is given by

\Delta v=\beta v_0(T_f-T_i)\\\Rightarrow T_f=\frac{\Delta v}{\beta v_0}+T_i\\\Rightarrow T_f=\frac{150-147.5}{1120\times 10^{-6}\times 147.5}+273.1\\\Rightarrow T_f=288.2\ K

The temperature of the ethyl alcohol should be 288.2 K to reach 150 mL

8 0
3 years ago
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