Answer:
b. it has the same centripetal acceleration as car A.
Explanation:
According to the question, the data provided is as follows
Constant speed of car A = 20 m/s
Constant tangential acceleration until its speed is 40 m/s
Based on the above information, the true statement is the same centripetal acceleration as car A because
As we know that
Centripetal acceleration is
where,
= velocity
r = radius of the path
Now if both car A and car B moving in the same or identical circular path having the same velocity so in this case there is the same centripetal acceleration for that particular time
hence, the second option is correct
When a car<span> rounds a corner at a constant </span>speed<span>, its acceleration is zero. Suppose you are in a </span>car<span> that is going around a curve. The speedometer reads a constant 30 miles per hour. ... </span>Describe the speed<span> of the object from 4-6 seconds using the distance vs. time graph.</span>
When the ball reaches its original position, it will have the same speed (but would be traveling in the opposite direction). So the average speed is
regardless of how long the ball was in the air.
Answer:
A. you would want to use the 12 ound ball and the 18 mph speed in order to transfer the most kinetic energy
B. KE= 1/2 MV^2 so you would want to maximize both your Mass(weight of the ball) and Velocity(speed of the roll) in order to achive the greatest KE.
C. see image
Explanation:
Full disclosure not totally sure what you are being asked in the last one but I put togethere a rough sketch that is my best guess.
