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3 years ago

a 0.500 M. solution is to be diluted to 500.0 mL of a 0.150 M soulution. How many mL of the 0.500 M solution are required

Chemistry

1 answer:

Nastasia [14]3 years ago

5 0

Http://www.wasatch.edu/cms/lib/UT01000315/Centricity/Domain/647/dilution%20problems%20answers.pdf it would be question 5 if you can read it.

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A hydrate of iron (ii) sulfite is known to contain 44.26% mater. what is the correct name of the hydrate

stellarik [79]

The correct name of the hydrate iron (ii) sulfite is iron(ii)sulfite heptahydrate
it is gotten as below

find the % composition of FeSO4 = 100-44.26 =55.74 %

find the mole of FeSO4 and H20
= % composition/molar mass

FeSo4 =55.74/151.9 = 0.367 moles
H2O = 44.26/18 =2.459 moles

find the mole ratio by diving each mole with smallest mole
FeSO4 = 0.367/0.367 = 1
H2O = 2.459/0.367 = 7

therefore the name is iron (ii) sulfite heptahydrate is it has seven water molecules

6 0

4 years ago

If you needed a 1.5 x 1 0-4 M solution of a compound that has a molar mass of 760 g/mol, what would it concentration be in part

motikmotik

Answer:

114 ppm

Explanation:

Data obtained from the question include:

Conc. of compound in mol/L = 1.5×10¯⁴ mol/L

Molar mass of compound = 760 g/mol

Conc. in ppm =..?

Next, we shall determine the concentration of the compound in grams per litre (g/L) . This is illustrated below:

Conc. in mol/L = conc. in g/L / Molar mass

1.5×10¯⁴ = conc. In g/L / 760

Cross multiply

Conc. in g/L = 1.5×10¯⁴ x 760

Conc. in g/L = 0.114 g/L

Next, we shall convert 0.114 g/L to milligrams per litre (mg/L). This is illustrated below:

1 g/L = 1000 mg/L

Therefore, 0.114 g/L = 0.114 x 1000 = 114 mg/L

Finally, we shall convert 114 mg/L to parts per million (ppm). This is illustrated below:

1 mg/L = 1 ppm

Therefore, 114 mg/L = 114 ppm

From the calculations made above,

1.5×10¯⁴ mol/L Is equivalent to 114 ppm.

6 0

3 years ago

What are the elements that make up aspirin

lina2011 [118]

<span>I believe the elements that make up aspirin are carbon, hydrogen and oxygen. </span>

4 0

4 years ago

Read 2 more answers

For the following, identify the most likely value for x.a. BHx b. CHx c. NHx d. CH2Clx

vekshin1

Given :

a. $BH_x$ b. $CH_x$ c. $NH_x$ d. $CH_2Cl_x$ .

To Find :

Find the most likely vale of x for each one .

Solution :

a . $BH_x$

Because boron have valency of 3 .

So , x = 3 .

b . $CH_x$

Valency of carbon is 4 .

x = 4 .

c . $NH_x$

Valency of nitrogen is 3 .

Therefore , x = 3 .

d . $CH_2Cl_x$

Now ,we know valency of carbon is 4 and hydrogen is 1 .

Also , two hydrogen are already there .

So , only 2 electrons left to share .

Since , chlorine have valency of 1 .

Therefore , only 2 electrons of chlorine can connect .

x = 2 .

Hence , this is the required solution .

5 0

4 years ago

Hemoglobin has a much greater affinity for carbon monoxide than oxygen. which principle explains why a hyperbaric chamber (conta

babunello [35]

Hemoglobin has a much greater affinity for carbon monoxide than oxygen. In a hyperbaric chamber (containing high levels of oxygen) can treat carbon monoxide poisoning, by displacing carbon monoxide from Hemoglobin competitively.

Hemoglobin has a much greater affinity for carbon monoxide than oxygen. This is because, a coordinate bond is formed with Carbon monoxide and Haem structure of the hemoglobin.

Carbon monoxide with Hemoglobin is called as Carboxy haemoglobin.

Presence of oxygen displaces the Carbon monoxide with Hemoglobin that is formed due to poisoning.

Hyperbaric chamber is a chamber which contains pure oxygen in a chamber. The atmospheric pressure is kept about three to four times than the normal, such that the replacement of Carbon monoxide from Haem can occur as fast as possible since this reduces the half life of the Carboxy haemoglobin.

It is advisable not to treat Carbon monoxide poisoning yourself.

Hyperbaric oxygen is used to treat the following conditions as well:

Infections
Wounds
Air bubble is blood

Learn more about Carbon Monoxide here, brainly.com/question/11313918

#SPJ4

3 0

2 years ago