A flask contains a gas mixture of hydrogen, nitrogen and methane. The total pressure of the mix is 3.0 atm. The partial pressure
1 answer:
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<span>the pH of a 0.050 M triethylamine, is 11.70
</span>
For triehtylamine,
, the reaction will be
and we know, pH = -log[H+] and pOH = -log[OH-]
And![kb = \frac{( [( C_{2}H_{5})_{3}NH^{+} ]* OH^{-} )}{[( C_{2}H_{5})_{3}N]}](https://tex.z-dn.net/?f=kb%20%3D%20%20%5Cfrac%7B%28%20%5B%28%20C_%7B2%7DH_%7B5%7D%29_%7B3%7DNH%5E%7B%2B%7D%20%5D%2A%20%20OH%5E%7B-%7D%20%29%7D%7B%5B%28%20C_%7B2%7DH_%7B5%7D%29_%7B3%7DN%5D%7D%20)
thus, [OH-] =(5.3 ^ 10-4) ^2 / 0.050
=0.00516 M
Thus, pOH = 2.30
pH = 14 - pOH = 11.7
</span>
For triehtylamine,
and we know, pH = -log[H+] and pOH = -log[OH-]
Also, pOH + pH = 14
Now, the Kb value = 5.3 x 10^-4And
thus, [OH-] =(5.3 ^ 10-4) ^2 / 0.050
=0.00516 M
Thus, pOH = 2.30
pH = 14 - pOH = 11.7
Answer:
C. Plug the unknowns into the ideal gas law formula.
Explanation:
Gay-Lussac's law states that:
"For a constant mass of an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"
Mathematically, it can be written as:
where
p1 is the initial pressure
T1 is the initial temperature (in Kelvin)
p2 is the final pressure
T2 is the final temperature (in Kelvin)
Therefore, in order to solve for one of the 4 variables, the following steps must be adopted:
A. List your knowns and unknowns.
B. Convert temperature to kelvin.
D. Solve for the unknown.
While the following step is not needed:
C. Plug the unknowns into the ideal gas law formula.
Because we do not need to use the ideal gas law formula.