Question

Harper's house is 30 feet wide and 45 feet long. On a scale drawing, the house is 4 inches wide and 6 inches long, and Harper's bedroom is 1.2 inches wide and 1.6 inches long.
What are the actual measurements of Harper's bedroom?


Harper's bedroom is ____ feet wide and ____ feet long

Answer 1

Answer:

Harper's bedroom is $9$ feet wide and $12$ feet long

Step-by-step explanation:

step 1

Find the scale of the drawing

we know that

Harper's house is $30$ feet wide and $45$ feet long. On a scale drawing, the house is $4$ inches wide and $6$ inches long

The scale is equal to

$\frac{4}{30}\frac{inches}{feet} =\frac{6}{45}\frac{inches}{feet}=\frac{1}{7.5}\frac{inches}{feet}$

step 2

Find the the actual measurements of Harper's bedroom

we know that

Harper's bedroom on a scale drawing is $1.2$ inches wide and $1.6$ inches long

The scale drawing is $\frac{1}{7.5}\frac{inch}{feet}$

therefore

To obtain the actual measurements multiply the measurements on a scale drawing by $7.5$

so

$wide=1.2*7.5=9\ ft$

$long=1.6*7.5=12\ ft$

Answer 2

So 30 ft is equal to 4 Inc on scale !
therefore 1.2 on scale will be (30/4)×1.2= 9 ft wide !!

6 Inc on scale is equal to 45 feet on actual
so 1.6 will be (45/6)×1.6= 12 ft long


so answer is 9 ft wide and 12 ft long !!