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Furkat [3]
3 years ago
15

Convert the following equation from standard form to slope intercept form 3x-8y=12

Mathematics
2 answers:
kenny6666 [7]3 years ago
8 0

Answer:

Step-by-step explanation:

 Slope = 0.750/2.000 = 0.375

 x-intercept = -12/3 = -4

 y-intercept = 12/8 = 3/2 = 1.50000

Pavlova-9 [17]3 years ago
5 0

Answer:

y=\frac{3}{8}x - \frac{3}{2}

Step-by-step explanation:

Hi there!

We are given the equation 3x-8y=12, and we want to convert it from standard form into slope intercept form

  • Standard form is ax+by=c, which is the form that the equation is in right now
  • Slope-intercept form is y=mx+b, where m is the slope and b is the y intercept,  which is the form we want the equation to be in

In slope-intercept form, y is isolated on one side, while everything else is on the other side.

In other words, we'll need to solve for y in order to convert from standard to slope-intercept form

Start by subtracting 3x from both sides

3x-8y=12

-3x      -3x

________

-8y = -3x + 12

Like any equation, we want just the value of y by itself. So divide both sides by -8

y=\frac{-3}{-8}x + \frac{12}{-8}

You may simplify the equation; \frac{-3}{-8} is the same as just \frac{3}{8}.

You may divide by 4 on both the numerator and the denominator of  \frac{12}{-8}, to get \frac{3}{-2} and then bring the minus sign up in front (-\frac{3}{2})

The equation will now be

y=\frac{3}{8}x + -\frac{3}{2}, or y = \frac{3}{8}x - \frac{3}{2}

Hope this helps!

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The accompanying data represent the daily​ (for example, Monday to​ Tuesday) movement of Johnson​ & Johnson​ (JNJ) stock for
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Supposing that the stock increases in 37 days, the 95% confidence interval for the proportion of days JMJ stock increases is: (0.484, 0.7292)

  • The lower bound is of 0.484.
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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

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Supposing that it increases on 37 out of 61 days:

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95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.  

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 - 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.484

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6066 + 1.96\sqrt{\frac{0.6066(0.3934)}{61}} = 0.7292

The ​95% confidence interval for the proportion of days JMJ stock increases is (0.484, 0.7292), in which 0.484 is the lower bound and 0.7292 is the upper bound.

The interpretation is that we are <u>95% sure that the true proportion</u> of all days in which the JMJ stock increases <u>is between 0.484 and 0.7292.</u>

A similar problem is given at brainly.com/question/16807970

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Answer:

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7 0
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