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Julli [10]
2 years ago
11

Plz i need help fast im timed!!!!!!

Physics
2 answers:
IRINA_888 [86]2 years ago
8 0
Answer: hope this helps

professor190 [17]2 years ago
4 0

Answer:

sorry i throght i had the answer

Explanation:

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What is the wavelength of light (nm) that has a frequency of 6.44 x 1013 s-1?
lesantik [10]
4660

Hope this helped!
STSN
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3 years ago
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Lee skated 36 miles in 3 hours. What was the speed at which Lee
Zanzabum

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12mph

Explanation:

36/3=mph

8 0
3 years ago
Un pintor de 75.0 kg sube por una escalera de 2.75 m que está inclinada contra una pared vertical. La escalera forma un ángulo d
dezoksy [38]

Answer:

Work done, W = 1786.17J

Explanation:

The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "

Mass of a painter, m = 75 kg

He climbs 2.75-m ladder that is leaning against a vertical wall.

The ladder makes an angle of 30 degrees with the wall.

We need to find the work done by the gravity on the painter.

The angle between the weight of the painter and the displacement is :

θ = 180 - 30

= 150°

The work done by the gravity is given by :

W=Fd\cos\theta\\\\=75\times 10\times 2.75\times \cos30\\\\=1786.17\ J

Hence, the required work done is 1786.17 J.

6 0
2 years ago
If you shout at a cliff wall that is 440 m away and the air temperature is at 25 °C, how long will it take before you hear your
ira [324]
The speed of sound at T=25°C is Vs=346 m/s. So the sound has to reach the cliff and return back to you so the path it needs to travel is s=2*440 m = 880 m.
Since the speed of sound is constant s=Vs*t, and t= s/Vs=880/346=2.54335 s. You will hear the echo after t=2.54335 s after you shouted. 
7 0
3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.330. At what minimum rate wo
Helga [31]

Answer:3.23 m/s^2

Explanation:

Given

\mu_s =0.330

Frictional Force is balanced by force due to car acceleration

Frictional force F_s

F_s=ma_{min}

\mu_sN=ma_{min}

\mu_s\cdot mg=ma_{min}

a_{min}=\mu_s \cdot g=0.330\times 9.8=3.23 m/s^2

6 0
3 years ago
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