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swat32
3 years ago
6

You accidentally drop a book out of the window of a tall building. Assuming

Physics
2 answers:
Anettt [7]3 years ago
7 0

Answer:

very fast

Explanation:

gravity

cupoosta [38]3 years ago
6 0

Answer:

b

Explanation:

after 28 seconds anything will be 9.8 ps

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To which class of compounds does ammonia belong?
12345 [234]
Depends what you want . 1 it belongs to hydrides , it is nitrogen hydride . 2 if you want to use the property given ( and i presume you mean pH ) then it is a base . 3 because it is a soluble base , it is called an alkali .
6 0
3 years ago
In your experiment, you measure a total deflection of 4.12 cm when an electric field of 1.10×103V/m is established between the p
Bond [772]

Answer:

B_0 = 1.69 \times 10^{-4}\ T

Explanation:

given,

total deflection = 4.12 cm

Electric field = 1.1 ×10³ V/m

plate length = 6 cm

distance between them = 12 cm

using formula

v_0 = \sqrt{\dfrac{q\epsilon_0d}{ym}(\dfrac{d}{2}+L)}

q = 1.6 × 10⁻¹⁹ C

m = 9.11 x 10⁻³¹ kg

d = 0.06 m

L = 0.12 m

v_0 = \sqrt{\dfrac{1.6 \times 10^{-19}\times 1.1 \times 10^{3}\times 0.06}{0.0412\times 9.11 \times 10^{-31} }(\dfrac{0.06}{2}+0.12)}

v_0 = 6496355.63 m/s

v_0 = \dfrac{E}{B_0}

B_0 = \dfrac{E}{v_0}

B_0 = \dfrac{1.1\times 10^{3}}{6496355.63}

B_0 = 1.69 \times 10^{-4}\ T

5 0
3 years ago
Find the orbital speed v for a satellite in a circular orbit of radius R.Express the orbital speed in terms of G, M, and R.
AlekseyPX
<h2>Answer:V=\sqrt{G\frac{M}{R}}  </h2>

The velocity of a satellite describing a circular orbit is <u>constant</u> and defined by the following expression:

V=\sqrt{G\frac{M}{R}}     (1)

Where:

G is the gravity constant

M the mass of the massive body around which the satellite is orbiting

R the radius of the orbit (measured from the center of the planet to the satellite).

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. I<u>t depends on the mass of the massive body.</u>

In addition, this orbital speed is constant because at all times <u>both the kinetic energy and the potential remain constant</u> in a circular (closed) orbit.

5 0
4 years ago
What do MRI and ultrasound have in common as diagnostic imaging techniques? Check all that apply.
Gennadij [26K]

Answer:

low risk for tissue damage

uses radio waves

the last three are not correct

:)

8 0
3 years ago
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Explain why is it easy to slip on a floor that is wet
zmey [24]
The water creates less friction between your foot and the ground
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3 years ago
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