Answer:
m(P4) = 46.175 (grams)
m (KClO3) = 149 (grams)
Explanation:
1) n(P4) = n(P4O10);
m(P4)/M(P4) = m(P4O10)/M(P4O10);
m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)
2) Analogously, 10n(P4O10) = 3n(KClO3)
m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).
Answer:
<em>The force exerted by each string is 25 N</em>
Explanation:
<u>Net Force</u>
The net force is the vector sum of forces acting on a body. The net force is a single force that represents the effect of the original forces on the body's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.
The picture described in the problem is hanging at rest supported by two vertical strings. This means that the net force acting on it is zero.
Assume the magnitude of each of these equal forces is F, and the picture has a weight of W=50 N, thus the net force is:
F + F - W
The positive signs indicate an upwards direction and the negative sign means a downwards direction. Since the net force is zero:
F + F - W = 0
2F = W
F = W/2 = 50 N/2
F = 25 N
The force exerted by each string is 25 N
Answer:
i don't know if this is right but here,9900 kgm/s
Explanation:
calculator UwU
Answer:
Take notes
Explanation:
Cuz it helps you stay on task
Answer:
The speed and direction of the tangled players is 2.89 m/s towards right.
Explanation:
Given;
mass of the player heading right, m₁ = 40 kg
initial velocity of the player heading right, u₁ = 9.0 m/s
mass of the player heading left, m₂ = 50 kg
initial velocity of the player heading left, u₂ = -2.0 m/s
let the speed of the tangled players = v
Apply the law of conservation of linear momentum;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(40 x 9) + (50 x - 2) = v(40 + 50)
360 - 100 = v(90)
260 = v(90)
v = 260 / 90
v = 2.89 m/s (towards right, since it is in position direction)
Therefore, the speed and direction of the tangled players is 2.89 m/s towards right.
