<h2>
The magnitude 24 (
) of the acceleration of the particle when the particle is not moving.</h2>
Explanation:
Given,
A particle moving along the x-axis has a position given by
m ........ (1)
To find, the magnitude (
) of the acceleration of the particle when the particle is not moving = ?
Differentiating equation (1) w.r.t, 't', we get
![\dfrac{dx}{dt} =\dfrac{d((24t-2.0t^3))}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7Bdx%7D%7Bdt%7D%20%3D%5Cdfrac%7Bd%28%2824t-2.0t%5E3%29%29%7D%7Bdt%7D)
⇒
....... (2)
⇒ ![24-6t^{2} = 0](https://tex.z-dn.net/?f=24-6t%5E%7B2%7D%20%3D%200)
⇒ ![t^{2}=2^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D%3D2%5E%7B2%7D)
⇒ t = 2 s
Again, differentiating equation (2) w.r.t, 't', we get
![\dfrac{d^2x}{dt^2} =-12t](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5E2x%7D%7Bdt%5E2%7D%20%3D-12t)
Put t = 2, we get
![\dfrac{d^2x}{dt^2} =-12(2)=24](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5E2x%7D%7Bdt%5E2%7D%20%3D-12%282%29%3D24)
Thus, the magnitude 24 (
) of the acceleration of the particle when the particle is not moving.
Answer:
B. 9.0 V
Explanation:
In parallel circuits, the voltage across each circuit is the same across each component, which is also equal to the total voltage of the power supplied. So in this case, the voltage across each resistor is still 9.0V.
The voltage only changes when the resistors can connected in series.
Elastic potential energy stored in a spring is
(1/2) · (spring constant) · (stretch or compress)² .
PE = (1/2) · (100 N/m) · (0.1 m)²
PE = (50 N/m) · (0.01 m²)
PE = (50 · 0.01) (N · m / m²)
PE = 0.5 N · m
PE = 0.5 Joule
Answer:
look at my Explanation
Explanation:
If the Maggie's mass is 100.0 kg and the truck is 1810 kg, calculate the magnitude of the net (unbalanced) force that can cause the acceleration.