Answer:
is there anything that is a hint? like a picture or a story?
Explanation:
The mass of the second coin for the given gravitation force is 20.9 g.
The given parameters;
- <em>distance between the two coins, r = 15 mm = 0.015 m</em>
- <em>mass of one coin, m₁ = 6.5 g = 0.0065 kg</em>
- <em>gravitational force between the coins = 4.03 × 10⁻¹¹ N</em>
The mass of the second coin is determined by applying Newton's law of universal gravitation as shown below;

Thus, the mass of the second coin for the given gravitation force is 20.9 g.
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That depends on a few things that you haven't told us about the setup.
So I'm going to assume one of them, and then give you the answer
in terms of another one:
-- Assume a Class-I lever . . . the fulcrum is between the load and the effort.
-- Then the effort needed to lift the load is
(the weight of the load) x (13 / the distance between the fulcrum and the effort)
(a) 
The average acceleration of the ship is given by

where
v is the final velocity
u is the initial velocity
t is the time elapsed
Here we have:
is the initial velocity
v = 0 is the final velocity
is the time elapsed
Substituting, we find

(b) 4.72 m/s
Assuming the acceleration is uniform, the average velocity of the ship is given by:

where
v is the final velocity
u is the initial velocity
Here we have:
v = 0
u = 9.44 m/s
So the average velocity of the ship is

Answer:
it takes 3 hours to travel
Explanation:
120 ÷ 40 = 3