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e-lub [12.9K]
3 years ago
9

When a golf club hits a 0.0459 kg ball at rest, it exerts a 2380 N force for 0.00100 s. What is the speed of the ball afterwards

? (Unit = m/s)

Physics
2 answers:
aksik [14]3 years ago
8 0

Answer:

51.85m/s

Explanation:

Given parameters:

Mass of ball  = 0.0459kg

Force  = 2380N

Time taken  = 0.001s

Unknown:

Speed of the ball afterwards  = ?

Solution:

To solve this problem, we use Newton's second law of motion:

   F = m x \frac{v - u}{t}  

F is the force

m is the mass

v is the final velocity

u is the initial velocity

t is the time taken

        2380  = 0.0459 x \frac{v- 0}{0.001}  

        0.0459v  = 2.38

                   v = 51.85m/s

stepladder [879]3 years ago
5 0

Answer:

2.38

Explanation:

F = dp/dt  --> dp = F*dt ---> p = F*t if F is constant over time so

p = 2380N* 0.001 s = 2.38 kg-m/s

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During which phase of the moon do neap tides occur?
Fynjy0 [20]

Answer:

First Quarter and Third Quarter.

Explanation:

Tides are formed as a consequence of the differentiation of gravity due to the Moon across to the Earth sphere.

Since gravity variates with the distance:

F = G\frac{m1\cdot m2}{r^{2}} (1)

Where m1 and m2 are the masses of the two objects that are interacting and r is the distance between them.

For example, seeing the image below, point A is closer to the Moon than point b, and at the same time the center of mass of the Earth will feel more attracted to the Moon than point B. Therefore, that creates a tidal bulge in point A and point B.

When the Sun and the Moon are alight with respect to the Earth, then the Sun tidal force contributes to the tidal force of the Moon over the Earth. That makes the high tides even higher (spring tides).

               

However, when the Sun is not in the same line than the Moon (the Moon is at 90° with respect to the Sun), then the low tides are higher and the high tides are lower. That scenario is known as neap tides.

           

Therefore, that happens when the Moon is at First Quarter and Third Quarter.

4 0
3 years ago
Read 2 more answers
In a large restaurant an average 60% customers ask for water with their meal. A random sample of 10 customers is selected. Find
Gekata [30.6K]

Answer:

a)P(6)=0.25

b)p(x

c)p(x\geq3)=0.9878

d)\sigma=\sqrt{2.4}=1.5492

Explanation:

From the question we are told that:

Population percentage p_\%=\60%

Sample size n=10

Let x =customers ask for water

Let y =customers dose not ask for water with their meal  

Generally the equation for y is mathematically given by

y=1-p_\%\\y=1-0.60\\y=0.40

Generally the equation for pmf p(x) is mathematically given by

P(x)=10C_x (0..6)^x(0.4)^{10-x}

a)

Generally the probability that exactly 6 ask for water is mathematically given by

P(x)6=10C_6 (0..6)^6(0.4)^{10-6}

P(6)=0.25

b)

Generally the probability that  less than 9 ask for water with meal  is mathematically given by

p(xg)

p(x

p(x

p(x

c)

Generally the probability that  at least 3 ask for water with meal  is mathematically given by

p(x\geq3)=1-p(x

p(x\geq3)=1-[p(0)+p(1)+p(2)]

p(x\geq3)=1-[0.00001+0.0015+0.0106]

p(x\geq3)=1-[0.0122]

p(x\geq3)=0.9878

d)

Generally the mean and standard deviation of sample size is mathematically given by

Mean

\=x=np=10(0.6)=6

Standard deviation

v(x)=npq=10(0.6)(0.4)=2.4

\sigma=\sqrt{2.4}=1.5492

4 0
3 years ago
Which types of numbers does scientific notation best describe?
Travka [436]
The correct answer is
<span>c) very small and very large

Let's see this with a few examples:
1) if we have a very small number, such as
</span>0.0000000001
<span>we see that we can write it easily by using the scientific notation:
</span>1\cdot 10^{-10}
<span>2) Similarly, if we have a very large number:
</span>10000000000
<span>we see that we can write it easily by using again the scientific notation:
</span>1 \cdot 10^{10}<span>
</span>
4 0
3 years ago
An object is propelled along a straight-line path by a force. If the new force were doubled, is acceleration would
Aneli [31]
Still go straight but would obviously go up in speed!!





Hope this helps plz mark as brainlist and 5 star
6 0
3 years ago
Read 2 more answers
A 10-kg cart moving at 5 m/s collides with a 5-kg cart at rest and causes it to move 10 m/s. Which principle explains the result
Over [174]
B) law of conservation of momentum

It states that the total momentum of a system before impact is the same as the total momentum of the system after impact.

In this case total momentum before impact:

10kg*5m/s  + 5kg * 0m/s = 50 kg m/s

After Impact:

10kg*0m/s + 5kg*10m/s = 50 kg m/s

You can see the momentum before and after impact is same as 50 kg m/s  

Of course we assumed that the first cart stopped after the impact, and there are no energy losses.
7 0
3 years ago
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