Answer:
45.09 m/s^2
Explanation:
from the question we were given the following parameters
mass = 931.9 kg
initial velocity (V1) = 0 m/s ( since it started from rest )
final velocity (V2) = 25.7 m/s
time (t) = 0.57 s
The average acceleration is given by:
a = ( V2 - V1 ) / t
therefore
a = (25.7 - 0) / 0.57 = 45.09 m/s^2
Answer: D) 3.2 × 10^8
Explanation: Insulators are best described as materials which are poor conductors of electricity and hence do not allow passage of electricity through them. Resistivity are hence used to describe property or characteristic of a material which does not allow the flow or passage of electric current.
In summary, materials which high resistivity values are referred to as Insulators. Conversely, those with low resistivity or high conductivity values are called conductors while those with intermediate values are named semiconductors.
In the question given above, the material with a resistivity value of 3.2 × 10^8 - - - has a very high resistivity value (320000000Ω), the other options given have very low resistivity values ; 0.0000000017, etc and are most likely to be conductors due to their excessively low resistivity values.
B. Transverse Wave this is the correct answer
Answer:
Explanation:
The application of Gauss's law is used in the derivation as shown with detailed step by step in the attached file.
The potential difference on this spherical capacitor is ΔV = Va - Vb = kQ/a - kQ/b = kQ(1/a - 1/b)
Answer:
A spring whose spring constant is 200 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 inch.
Step 1 of 4
The force at any point during the deflection of the spring is given by,
where is the initial force
and x is the deflection as measured from the point where the initial force occurred.
The work required to compress the spring is
Therefore work required to compress the spring is
The work required to compress the spring in Btu is calculated by
Where 1Btu =778
The work required to compress the spring,
eman Asked on February 19, 2018 in thermal fluid Sciences 4th solutions.
Explanation:
