Question

A ball is rolling along a road at the top of a hill, at a velocity of 10.0 km/hr. The ball rolls down a 50.0 m high hill. Neglecting air and road resistance, estimate the velocity of the ball at the bottom of the hill. Upload your solution.

Answer 1

Answer:

$v_f = 31.44 m/s$

Explanation:

initial height of the ball is given as

$H = 50.0 m$

initial speed of the ball is given as

$v = 10.0 km/h$

now we know that

$v = 10 \times \frac{1000}{3600}$

$v = 2.78 m/s$

now by energy conservation we can say

initial kinetic energy + initial potential energy = final kinetic energy + final potential energy

$\frac{1}{2}mv_i^2 + mgh_1 = \frac{1}{2}mv_f^2$

$\frac{1}{2}(2.78)^2 + (9.81)(50.0) = \frac{1}{2}v_f^2$

$v_f = 31.44 m/s$