The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U = m ΔT
U = Energy
= Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
= 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
To know more about energy required to raise temperature
brainly.com/question/12372041
#SPJ1
Answer:
D = 26.97 m
Explanation:
given,
you walk 12.5 m in a direction exactly 19° south of west
after that 19.5 m in a direction exactly 39° west of north.
distance calculation from the starting point = ?
D₁ = d₁ cos θ
D₁ = 12.5 x cos 19°
D₁ = 11.82 m
D₂ = d₂ cos θ
D₂ = 19.5 x cos 39°
D₂ = 15.15 m
distance from the starting point
D = D₁ + D₂
D = 11.82 + 15.15
D = 26.97 m
Distance from the starting point is equal to 26.97 m
Global warming is the unusually rapid increase in Earth's average surface temperature over the past century primarily due to the greenhouse gases released as people burn fossil fuels. ... Temperatures are certain to go up further. Despite ups and downs from year to year, global average surface temperature is rising.
Answer:
32s
Explanation:
We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:
and the police car distance:
Since they both travel the same distance x, we can equal both formulas and solve for t:
Two solutions exist to the equation; the first one being
The second solution will be:
This result allows us to confirm that the police car will take 32s to catch up to the speeder