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4 years ago

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A moving small car has a head-on collision with a large stationary truck 7.3 times the mass of the car. Which statement is true

about the direction of the car after the collision if the collision is inelastic?

1 answer:

san4es73 [151]4 years ago

7 0

Answer:

The car would speed off 2x's as fast as the speed of the heavy truck provided the the collision is an elastic collision where there's no or little friction occurring within the scenario.

Explanation:

Newton's law proves that an object with a greater mass can move objects of lesser mass at greater distances and speed.

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If you want to calculate the acceleration of a car, you should _____ the change in velocity of the car by the time interval.

Neporo4naja [7]

Answer:

Your awnser is B. Increase

Explanation:

5 0

3 years ago

Read 2 more answers

Two circular loops carry identical currents, but the radius of one loop is twice that of the other.

Valentin [98]

The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Explanation:

The magnetic field strength at the center of a current-carrying circular loop is

$B=\frac{\mu_0 I}{2R}$

where

$\mu_0$ is the vacuum permeability

I is the current

R is the radius of the loop

For the first circular loop, we have

$B_1 = \frac{\mu_0 I_1}{2R_1}$

The second loop has

$I_2 = I_1$ (same current)

$R_2 = 2R_1$ (twice the radius)

So, the magnetic field at the centre of the second loop is

$B_2 = \frac{\mu_0 I_2}{2R_2}=\frac{1}{2}(\frac{\mu_0 I_1}{2R_1})=\frac{B_1}{2}$

So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Learn more about magnetic fields:

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3 years ago

Diana observed that the plants in her garden were not growing well due to poor soil conditions. She tested the soil and used the

n200080 [17]

The appropriate answer is c. silty clay loam. This is the most likely soil that was present in the garden before sand was added to balance it. This type of soil contains an even mix of silt and clay. This type of soil does not drain well and tends to hold water. This would not be suitable for most garden variety plants. Adding sand to the soil ensures better drainage and removes moisture that would rot roots or create conditions for fungi to develop.

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3 years ago

When electrons are transferred from one atom to another, and the two atoms unite as a result of the opposite charges, a(n) _____

podryga [215]

Answer: ionic compound

Explanation:

An ionic compound is formed when one element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

For formation of sodium chloride:

Electronic configuration of sodium:

$[Na]=1s^22s^22p^63s^1$

Sodium atom will loose one electron to gain noble gas configuration and form sodium cation with +1 charge.

$[Na^+]=1s^22s^22p^63s^0$

Electronic configuration of chlorine:

$[Cl]=1s^22s^22p^63s^23p^5$

Chlorine atom will gain one electron to gain noble gas configuration and form chloride ion with -1 charge.

$[Cl^-]=1s^22s^22p^63s^23p^6$

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic compound.

4 0

3 years ago

A football wide receiver rushes 16 m straight down the playing field in 2.9 s (in the positive direction). He is then hit and pu

vredina [299]

Answer:

a) $v_1=5.5172\ m.s^{-1}$

b) $v_2=-1.5152\ m.s^{-1}$

c) $v_3=4.6154\ m.s^{-1}$

d) $v_{avg}=3.8462\ m.s^{-1}$

Explanation:

Given:

distance down the field in the first interval, $d_1=16\ m$

time duration of the first interval, $t_1=2.9\ s$

distance down the field in the second interval, $d_2=-2.5\ m$

time duration of the second interval, $t_2=1.65\ s$

distance down the field in the third interval, $d_3=24\ m$

time duration of the third interval, $t_3=5.2\ s$

a)

velocity in the first interval:

$v_1=\frac{d_1}{t_1}$

$v_1=\frac{16}{2.9}$

$v_1=5.5172\ m.s^{-1}$

b)

velocity in the second interval:

$v_2=\frac{d_2}{t_2}$

$v_2=\frac{-2.5}{1.65}$

$v_2=-1.5152\ m.s^{-1}$

c)

velocity in the third interval:

$v_3=\frac{d_3}{t_3}$

$v_3=\frac{24}{5.2}$

$v_3=4.6154\ m.s^{-1}$

d)

We know that the average velocity is given as the total displacement per unit time.

$v_{avg}=\frac{d_1+d_2+d_3}{t_1+t_2+t_3}$

$v_{avg}=\frac{16-2.5+24}{2.9+1.65+5.2}$

$v_{avg}=3.8462\ m.s^{-1}$

3 0

3 years ago