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Vesnalui [34]
3 years ago
10

4

Chemistry
1 answer:
makkiz [27]3 years ago
8 0
A forest would have have the most fertile soil
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1. What is the density, in g/cm², of a substance weighing 22.2 cg with dimensions of 0.333
RUDIKE [14]
  • Mass=22.2cg=2.22g

Volume:-

\\ \tt\longmapsto 0.333(0.444)(0.555)=0.08cm^3

So

\\ \tt\longmapsto Density=\dfrac{Mass}{Volume}

\\ \tt\longmapsto Density=\dfrac{2.22}{0.08}=27.75g/cm^3

7 0
2 years ago
Why isnt iron bromide magnetic
kramer
There is two of these questions
4 0
3 years ago
Consider the following reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially contains 1.6 M COCl2. Determine the equi
professor190 [17]

Answer:

The equilibrium concentration of CO is 0.0361 M

Explanation:

Step 1: Data given

Kc = 8.33 *10^-4

Molarity of COCl2 = 1.6 M

Step 2: The balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate final concentrations

The initial concentration of COCl2 = 1.6M

The initial concentration of CO and Cl2 = 0M

There will react xM of COCl2

Since the mole ratio is 1:1

The final concentration of CO and Cl2 will be X M

The final concentration of COCl2 will be (1.6 -X)M

Step 4: Define Kc

Kc=  [CO] *[Cl2] /  [COCl2]  = 8.33*10^-4

Kc = X*X / 1.6-X = 8.33 * 10^-4

8.33 * 10^-4  = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

X² + 8.33*10^-4 X  - 0.0013328= 0

X = 0.0361 M = [CO] = [Cl2]

[COCl2] = 1.6 - 0.0361 = 1.5639 M

To control this we can calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833

5 0
3 years ago
The value of the equilibrium constant for the following chemical equation is Kr 40 at 25°C. Calculate the solubility of Al(OH)s(
dedylja [7]

Answer:

0,040 M

Explanation:

The global reaction of the problem is:

Al(OH) (s) + OH⁻ ⇄ Al(OH)₂⁻(aq) K= 40

The equation of equilibrium is:

K = \frac{[Al(OH)_{2} ^-]}{[Al(OH)][OH^-]}

The concentration of OH⁻ is:

pOH = 14 - pH = <em>3</em>

pOH = -log [OH⁻]

[OH⁻] = 1x10⁻³

Thus:

40 = \frac{[Al(OH)_{2} ^-]}{[Al(OH)][1x10^{-3}]}

<em>0,04M =  \frac{[Al(OH)_{2} ^-]}{[Al(OH)]}</em>

This means that 0,04 M are the number of moles that the solvent can dissolve in 1L, in other words, solubility.

I hope it helps!

7 0
3 years ago
Please help mw with this
mart [117]

Answer:

I cannot see any picture

Explanation:

Please put a picture

7 0
3 years ago
Read 2 more answers
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