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2 years ago

Dur rn help pls ))))))))))

Mathematics

1 answer:

Vadim26 [7]2 years ago

3 0

Answer:

A is correct good luck bud

Step-by-step explanation:

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Claudia is reading a book that has 360 pages. she read some of the book last week. she plans to read 46 pages. when she does, sh

gladu [14]

She read 242 pages. I got that by finding what (4/5) x (360) was which is 288 and then subtracted 46 to see what was left over which is 242

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3 years ago

Use the order of operations and the digits 2, 4, 6, and 8 to create an expression with a value of 2

Naya [18.7K]

4÷(6-(8÷2))=2

Do the order of operations, and the end value will be 2.

Do you understand how I got that? Good luck by the way!

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3 years ago

Find the area of each sector. Show your work.

hodyreva [135]

Area of the shaded sector = (120/360) * pi * 10^2

= 104.72 square units

Area of the other sector = 2 * 104.72 = 209.44 sq units

6 0

3 years ago

Cathy uses 3/4 teaspoon of vanilla in a batch of cookies. How many teaspoons are needed for 8 batches of cookies

34kurt

6 teaspoons
3/4 * 8 is 24/4
24/4= 6
So you need 6 teaspoons

8 0

3 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago