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deff fn [24]
2 years ago
8

What are some potential risks and safety concerns that come with lifelong fitness? Given your activity level, what minor or majo

r injury risks do you face on a regular basis? How do you protect yourself from these risks?
Physics
1 answer:
azamat2 years ago
7 0
These include cardiovascular disease, heart failure, stroke, certain cancers, osteoporosis, obesity, type 2 diabetes, and hypertension (Mo A recent study found that higher levels of total daily sitting time were associated with an increased risk of cardiovascular disease and diabetes, independent of physical activity
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The average density of the body of a fish is 1080 kg/m3. To keep from sinking, the fish increases its volumeby inflating an inte
Dimas [21]

Answer:

f = 8 %

Explanation:

given,

density of body of fish = 1080 kg/m³

density of air = 1.2 Kg/m³

density of water = 1000 kg/m²

to protect the fish from sinking volume should increased by the factor f

density of fish + density of water x increase factor = volume changes in water                                                    

1080 +f x 1.2 =(1 + f ) x 1000                

1080 + f x 1.2 = 1000 + 1000 f      

998.8 f = 80                                  

f = 0.0800                            

f = 8 %                                        

the volume increase factor of fish will be equal to f = 8 %

7 0
3 years ago
What affect does friction have on motion
satela [25.4K]

Answer: friction reduces the speed during motion

Explanation:

The more the friction, the lesser the speed during motion

3 0
3 years ago
Help pls they are all going to have the same answers.
Liula [17]
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4 0
3 years ago
Please help me on this
Dafna1 [17]
I’m pretty sure the answer is A
5 0
2 years ago
A paperweight consists of a 8.55-cm-thick plastic cube. Within the plastic a thin sheet of paper is embedded, parallel to opposi
ella [17]

Answer:

\mu=1.5322

Explanation:

Given:

Thickness of the paperweight cube, x=8.55\ cm

apparent depth from one side of the inbuilt paper in the plastic cube, i=4.02\ cm

apparent depth from the other side of the inbuilt paper in the plastic cube, i'=1.56\ cm

Now as we know that refractive index is given as:

\rm \mu=\frac{real\ depth}{apparent\ depth}

  • Let the real depth form first side of the slab be, d
  • Then the depth from the second side of the slab will be, d'=x-d=8.55-d

Since refractive index for an amorphous solid is an isotropic quantity so it remains same in all the direction for this plastic.

\mu=\mu'

\frac{d}{i} =\frac{d'}{i'}

\frac{d}{4.02}=\frac{8.55-d}{1.56}

d=6.1597\ cm

Now the refractive index:

\mu=\frac{d}{i}

\mu=\frac{6.1596}{4.02}

\mu=1.5322

7 0
2 years ago
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