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ivanzaharov [21]
4 years ago
14

Balance the following chemical equations

Physics
1 answer:
IrinaVladis [17]4 years ago
4 0

Answer:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character.

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Example: Fe{3+} + I{-} =...

Substitute immutable groups in chemical compounds to avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2...

Explanation:

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A soccer ball is kicked from point Pi at an angle above a horizontal field. The ball follows an ideal path before landing on the
Nutka1998 [239]

Answer:

A. The horizontal velocity vector points to the right & equals v cos θ.

Explanation:

The motion describes a parabolic path, where the horizontal speed is constant and the horizontal velocity vector always points to the right and equals v*cos θ.

8 0
3 years ago
A wall, acted upon by a force of 20 N, does not move. The work done on the wall in this process is
jenyasd209 [6]

Answer:

0 (Zero)

Explanation:

Definition of work done states that ,

Work done on an object is the force applied on that object in the direction of Displacement of the object .

means that ,

W = F.dS (Dot product of Force and displacement)

When the wall is acted upon by the force of 20 N , Wall does not move ,

Thus , displacement of the wall is zero.

So, W = 20×0 = 0.

Thus, Work done on the wall is zero.

8 0
3 years ago
A man drags a 71-kg crate across the floor at a constant velocity by pulling on a strap attached to the bottom of the crate. The
Flura [38]

Answer:

T = 540 N   (to two significant digits)

Explanation:

Let the crate dimension L be from strap attachment to floor contact

Let T be the strap tension

sum moments about the floor contact point to zero

mg[½Lcos25] - Tsin61[Lcos25] + Tcos61[Lsin25] = 0

L is common to all terms, so divides out.

½(71)(9.8)cos25 = T(sin61cos25 - cos61sin25)

T = (71)(9.8)cos25 / (2(sin61cos25 - cos61sin25))

T = 536.428020...

7 0
3 years ago
The magnetic field lines outside a bar magnet
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The lines of magnetic field from a bar magnet form closed lines. By convention, the field direction is taken to be outward from the North pole and in to the South pole of the magnet.
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Which question would most likely fill in the blank
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Definitely not the last 2. My bet is on the first option. If it is wrong don't hit me please...
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