1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ivanzaharov [21]
4 years ago
14

Balance the following chemical equations

Physics
1 answer:
IrinaVladis [17]4 years ago
4 0

Answer:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character.

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Example: Fe{3+} + I{-} =...

Substitute immutable groups in chemical compounds to avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2...

Explanation:

You might be interested in
...............................................................help
chubhunter [2.5K]

Answer:

The maximum height that a cannonball fired at 420 m/s at a 53.0° angles is 5740.48m.

hmax = 5740.48 m

Explanation:

This is an example of parabolic launch. A cannonball is fired on flat ground at 420 m/s at a 53.0° angle and we have to calculate the maximum height that it reach.

V₀ = 420m/s and θ₀ = 53.0°

So, when the cannonball is fired it has horizontal and vertical components:

V₀ₓ = V₀ cos θ₀ = (420m/s)(cos 53°) = 252.76 m/s

V₀y = V₀ cos θ₀ = (420m/s)(cos 53°) = 335.43m/s

When the cannoball reach the maximum height the vertical velocity component is zero, that happens in a tₐ time:

Vy = V₀y - g tₐ = 0

tₐ = V₀y/g

tₐ = (335.43m/s)/(9.8m/s²) = 34.23s

Then, the maximum height is reached in the instant tₐ = 34.23s:

h = V₀y tₐ - 1/2g tₐ²

hmax = (335.43m/s)(34.23s)-1/2(9.8m/s²)(34.23s)²

hmax = 11481.77m - 5741.29m

hmax = 5740.48m

3 0
3 years ago
A big olive (* - 0.50 kg) lies at the origin of an xy coordinate system, and a big BrazlI nut (M - 1.5^kg) lie^s at the point (1
Afina-wow [57]

The <em>estimated</em> displacement of the center of mass of the olive is \overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m].

<h3>Procedure - Estimation of the displacement of the center of mass of the olive</h3>

In this question we should apply the definition of center of mass and difference between the coordinates for <em>dynamic</em> (\vec r) and <em>static</em> conditions (\vec r_{o}) to estimate the displacement of the center of mass of the olive (\overrightarrow{\Delta r}):

\vec r - \vec r_{o} = \left[\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot(m_{i}\cdot g + F_{i, x})}{\Sigma \limits_{i =1}^{2}(F_{i,x}+m_{i}\cdot g)} ,\frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot(m_{i}\cdot g + F_{i, y})}{\Sigma \limits_{i =1}^{2}(F_{i,y}+m_{i}\cdot g)} \right]-\left(\frac{\Sigma\limits_{i=1}^{2}r_{i,x}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}, \frac{\Sigma\limits_{i=1}^{2}r_{i,y}\cdot m_{i}\cdot g}{\Sigma \limits_{i= 1}^{2} m_{i}\cdot g}\right) (1)

Where:

  • r_{i, x} - x-Coordinate of the i-th element of the system, in meters.
  • r_{i,y} - y-Coordinate of the i-th element of the system, in meters.
  • F_{i,x} - x-Component of the net force applied on the i-th element, in newtons.
  • F_{i,y} - y-Component of the net force applied on the i-th element, in newtons.
  • m_{i} - Mass of the i-th element, in kilograms.
  • g - Gravitational acceleration, in meters per square second.

If we know that \vec r_{1} = (0, 0)\,[m], \vec r_{2} = (1, 2)\,[m], \vec F_{1} = (0, 3)\,[N], \vec F_{2} = (-3, -2)\,[N], m_{1} = 0.50\,kg, m_{2}  = 1.50\,kg and g = 9.807\,\frac{kg}{s^{2}}, then the displacement of the center of mass of the olive is:

<h3>Dynamic condition\vec{r} = \left[\frac{(0)\cdot (0.50)\cdot (9.807)+(0)\cdot (0) + (1)\cdot (1.50)\cdot (9.807) + (1)\cdot (-3)}{(0.50)\cdot (9.807) + 0 + (1.50)\cdot (9.807)+(-3)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (0)\cdot (3) + (2)\cdot (1.50)\cdot (9.807) +(2) \cdot (-2)}{(0.50)\cdot (9.807) + (3)+(1.50)\cdot (9.807)+(-2)}  \right]\vec r = (0,704, 1.233)\,[m]</h3>

<h3>Static condition</h3><h3>\vec{r}_{o} = \left[\frac{(0)\cdot (0.50)\cdot (9.807) + (1)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807) + (1.50)\cdot (9.807)}, \frac{(0)\cdot (0.50)\cdot (9.807) + (2)\cdot (1.50)\cdot (9.807)}{(0.50)\cdot (9.807)+(1.50)\cdot (9.807)}  \right]</h3><h3>\vec r_{o} = \left(0.75, 1.50)\,[m]</h3><h3 /><h3>Displacement of the center of mass of the olive</h3>

\overrightarrow{\Delta r} = \vec r - \vec r_{o}

\overrightarrow{\Delta r} = (0.704-0.75, 1.233-1.50)\,[m]

\overrightarrow{\Delta r} = (-0.046, -0.267)\,[m]

The <em>estimated</em> displacement of the center of mass of the olive is \overrightarrow{\Delta r} = -0.046\,\hat{i} -0.267\,\hat{j}\,[m]. \blacksquare

To learn more on center of mass, we kindly invite to check this verified question: brainly.com/question/8662931

3 0
2 years ago
Why would a person who weighs 100 lbs. on Earth weigh significantly more on Ju-piter?
Nitella [24]

Answer:

Is a

Explanation:

8 0
3 years ago
_____ is not a hormone.
Arlecino [84]

Answer:

So, the correct answer is 'Melatonin'.

Explanation:

thank me later

4 0
3 years ago
A seventh grade class is studying the solar system. A small group of students wanted to expand their studies to include the form
rodikova [14]

Answer:by. III

Explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • The magnetic strips on credit cards can become demagnetized. What type of magnet are they?
    9·2 answers
  • scientists analyze a piece of wood that was found in Jerusalem. they found that 50% of the carbon-14 was still remaining. how ol
    10·1 answer
  • An engine is any machine that can _____.
    15·1 answer
  • Which property of light remains unchanged when it enters a different medium?
    14·2 answers
  • A Carnot engine has a power output of 148 kW. The engine operates between two reservoirs at 17◦C and 727◦C. How much thermal ene
    15·1 answer
  • What allows us to stand upright and keeps us from falling through the ground?
    11·2 answers
  • Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
    14·1 answer
  • A 36 N net force acts on an 9 kg rock. What is the acceleration of the rock? *
    10·1 answer
  • What would the net force be on the box in the problems shown below.( both force and direction).​
    7·1 answer
  • Question 3
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!