The vector, which is often a small, circular piece of dna that can exist outside the bacterial chromosome, is known as a plasmid.
Bacteria and certain other microscopic species contain plasmids, which are tiny circular DNA molecules. Physically distinct from chromosomal DNA, plasmids multiply on their own. They normally contain only a few genes, including some linked to antibiotic resistance, and they can spread from one cell to another.
Recombinant DNA techniques are used by scientists to splice the genes they want to research into a plasmid. The inserted gene is duplicated along with the plasmid when it duplicates itself. Molecular cloning, the process of creating DNA molecules and introducing them into a host cell, uses plasmid vectors as the means of delivering recombinant DNA into the host cell.
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Answer:
3 long tails : 1 short tail
Explanation:
This question involves a single gene coding for tail length in mice. The allele for long tail (T) is dominant over the allele for short tail (t). This means that an heterozygous mice will possess the long tail length.
According to this question, in a cross between two hybrid or heterozygote mice i.e. Tt × Tt, the following gametes will be produced by each parent:
Tt - T and t
Using these gametes in a punnet square (see attached image), the following will be produced: TT, Tt, Tt and tt.
Offsprings with genotype TT, Tt and Tt will have a LONG TAIL while genotype tt will have a SHORT TAIL. Hence, the phenotypic ratio will be 3 long tails : 1 short tail.
Answer:
Explanation:
It is given that
B is the dominant allele which represents the black color
and b is the recessive allele which represents the white fur.
B being dominant will result into black color fur for genotype "Bb"
Given -
Frequency of black fur allele (p) is 
As per Hardy Weinberg's first law of equilibrium
Substituting the value of p in above equation, we get -
q represents the frequency for white fur allele
Frequency of white fur phenotype is
Frequency of homozygous black fur phenotype (BB) is
As per Hardy Weinberg's second law of equilibrium -
Combined frequency of homozygous and heterozygous black fur phenotype is
Answer:
The correct answer is B.It was necessary that each of the two phage components, DNA and protein, be identifiable upon recovery at the end of the experiment
Explanation:
Hershey and chase in his experiment lebelled the T₂ bacteriophage with radioactive sulfur and radioactive phosphorus separately. Then they infect E.coli with T₂phage and separated phage from bacteria by centrifugation.
Because DNA contains phosphorus not protein, cells infected with phage containing radioactive phosphorous showed radioactivity bacause DNA enters the cell not protein confirming DNA is the genetic material and radioactive sulfur was found in supernatant.
Answer:
The correct answer is: The statement is false.
Explanation:
Lymph capillaries DO NOT form a two-way system that moves lymph to and from the heart. The two-way system is only formed by blood capillaries; lymph capillaries are blind-ended, because they only move the lymph AWAY from the tissues.
Lymphatic capillaries are very thin and permeable vessels that locate between the cells and have the function to drain the extracellular fluid and the cells associated with it, which makes up the lymph. The lymph will ultimately return to the venous circulation.
