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4 years ago

It takes 8 seconds for a pulley system to lift a load that weights 400N to a height of 10 m. How much power is required?.

Physics

1 answer:

mariarad [96]4 years ago

3 0

Answer:

C. 500 watts

Explanation:

power is defined as the rate of work done

$power=\frac{work.done}{time}$

When a force causes a object to move, work is being done on the object by the force.

$work.done=force*displacement\\=400*10\\=4000J$

$power=\frac{4000J}{8s}\\=500 W$

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Four monitoring wells have been placed around a leaking underground storage tank. The wells are located at the corners of a 1-ha

Readme [11.4K]

Answer:

direction : West to East

magnitude : 6.0 * 10^-3

Explanation:

Given data :

Four ( 4 ) monitoring wells

location of wells = corners of 1-ha square

Total piezometric head in each well ;

NE corner = 30.0 m ;

SE corner = 30.0 m;

SW corner = 30.6 m;

NW corner = 30.6 m.

Calculate for the magnitude and direction of the hydraulic gradient

first step ; calculate for area

Area = ( 1 -ha ) ( 10^4 m^2/ha )

= 1 * 10^4 m^2

Distance between the wells = length of side

= √( 1 * 10^4 ) m^2

= 100 m

Direction of Hydraulic gradient is from west to east because the total piezometric head in the west = Total piezometric head in the east

Next determine The magnitude of the hydraulic gradient

= ( 30.6 - 30 ) / 100

= 6.0 * 10^-3

8 0

3 years ago

Determine the average velocity for an object that moves from x = 3.5 m to x =

SashulF [63]

-1.5-3.5 /2

-5/2=-2.5 m/s

4 0

3 years ago

A 1500-kg car traveling east with a speed of 25.0 m/s collides at an intersection with a 2500-kg van traveling north at a speed

IgorC [24]

Answer:

The direction and magnitude of velocity is 38.65° and 12.005 m/s

Explanation:

Given that,

Mass of car = 1500 kg

Speed of car = 25.0 m/s

Mass of van = 2500 kg

Speed of van =20.0 m/s

We need to calculate the velocity

Using conservation of energy

$m_{c}u_{i}+m_{v}u_{i}=(m_{c}+m_{v})v_{f}$

$1500(25i+0j)+2500(0+20j)=4000(v_{f})$

$v_{f}=\dfrac{1500\times25}{4000}i+\dfrac{1500\times20}{4000}j$

$v_{f}=9.375 i+7.5 j$

The magnitude of velocity

$|v_{f}|=\sqrt{(9.375)^2+(7.5)^2}$

$|v_{f}|=12.005\ m/s$

We need to calculate the direction

$\tan\theta=\dfrac{coefficient\ of\ j}{coefficient\ of\ i}$

$\tan\theta=\dfrac{7.5}{9.375}$

$\theta=\tan^{-1}0.8$

$\theta=38.65^{\circ}$

Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.

3 0

4 years ago

Can someone please help me solve these questions

yanalaym [24]

I can't read any of it... Please type a reply comment to this comment, with the questions, and I will help you.

3 0

4 years ago

The magnitude of the voltage induced in a conductor moving through a stationary magnetic field depends on the _______ and the __

Virty [35]

The correct answer is: Option (D) length, speed

Explanation:

According to Faraday's Law of Induction:

ξ = Blv

Where,

ξ = Emf Induced

B = Magnetic Induction

l = Length of the conductor

v = Speed of the conductor.

As you can see that ξ (Emf/voltage induction) is directly proportional to the length and the speed of the conductor. Therefore, the correct answer will be Option (D) Length, Speed

3 0

3 years ago

Read 2 more answers