Work Done (W) by the field is-6x 107 J,
<h3>What is Electric dipole?</h3>
A pair of opposite, non-coplanar, equally powerful electric charges that are in opposition to one another. An atom is said to have a "induced electric dipole" if the center of the negative cloud of electrons has moved a little bit away from the nucleus due to an external electric field. When the external field is taken away, dipolarity is lost.
Electric field (E) = 300 N/C
Dipole moment (p) = 2 x 10° Cm
Solution:
From the formula we know.
U = -pE cosФ
Here,
p Denotes Dipole moment.
E Denotes Electric field.
Ф Denotes angle b/w them
Now, as given, firstly the dipole is perpendicular to the electric field, so
angle (Ф1) will be 90° and now the dipole is rotated such that they are in same
direction so the angle (Ф2) will be 0°
So, let's find Change in Potential energy which will be equal to the work done
by the electric field.
ΔU = Uf - Ui
ΔU = [-pE*cos Ф2] - [-pE *cos Ф1]
ΔU = [-pE*cos Ф2] + pE *cos Ф1
ΔU = pE * [cos Ф2+ cos Ф1]
Substituting the values,
ΔU = pE * [cos 0° + cos 90°]
ΔU = pE * (-1 +0)
ΔU = -pE
ΔU = -2x 10^-9 × 300
ΔU = 6 x 10^(-9+2)
ΔU = 6 x 10^-7
W = ΔU = -6 x 10^-7
W = - 6 x 10 7 J
Work Done (W) by the field is - 6 x 10-7 J.
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