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3 years ago

Which describes the substances that form covalent bonds? a metal and a metalloid a metal and a nonmetal two nonmetals two metals

Physics

2 answers:

AVprozaik [17]3 years ago

6 0

Answer:

Explanation:

simple answer

VLD [36.1K]3 years ago

5 0

Answer:

Two non metals

Explanation:

Covalent bonding is a chemical bonding that involves sharing of electrons

a metal and a metalloid can be described as a metallic bond.

a metal and a nonmetal is an example that describes an ionic bonding

While two non metals is a typical example of a covalent bonding.

Therefore, two non metals describes the substances that form covalent bonds

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A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?

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Answer:

18 m

Explanation:

Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s

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Solving for the average velocity. avg v

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Temperature and pressure of a region upstream of a shockwave are 295 K and 1.01* 109 N/m². Just downstream the shockwave, the te

seraphim [82]

Answer:

change in internal energy 3.62*10^5 J kg^{-1}

change in enthalapy 5.07*10^5 J kg^{-1}

change in entropy 382.79 J kg^{-1} K^{-1}

Explanation:

adiabatic constant $\gamma =1.4$

specific heat is given as $=\frac{\gamma R}{\gamma -1}$

gas constant =287 J⋅kg−1⋅K−1

$Cp = \frac{1.4*287}{1.4-1} = 1004.5 Jkg^{-1} k^{-1}$

specific heat at constant volume

$Cv = \frac{R}{\gamma -1} = \frac{287}{1.4-1} = 717.5 Jkg^{-1} k^{-1}$

change in internal energy $= Cv(T_2 -T_1)$

$\Delta U = 717.5 (800-295) = 3.62*10^5 J kg^{-1}$

change in enthalapy $\Delta H = Cp(T_2 -T_1)$

$\Delta H = 1004.5*(800-295) = 5.07*10^5 J kg^{-1}$

change in entropy

$\Delta S =Cp ln(\frac{T_2}{T_1}) -R*ln(\frac{P_2}{P_1})$

$\Delta S =1004.5 ln(\frac{800}{295}) -287*ln(\frac{8.74*10^5}{1.01*10^5})$

$\Delta S = 382.79 J kg^{-1} K^{-1}$

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