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3 years ago

PLEASE HELP ME PLEASE

Physics

2 answers:

iVinArrow [24]3 years ago

7 0

Answer:

b should be the answer

Explanation:

its talking about the weather and not about the climate

cluponka [151]3 years ago

7 0

B would be correct. Climate is an average of an area over a period of time while temperature is a shorter time. Hope that helped

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The radioactive element radium (Ra) decays by a process known asalpha decay,in which the nucleus emits a helium nucleus. (Factoi

tamaranim1 [39]

<u>Answer:</u> The energy released in the decay process is $4.6800\times 10^{11}J$

<u>Explanation:</u>

The equation for the alpha decay of Ra-226 follows:

$_{88}^{226}\textrm{Ra}\rightarrow _{2}^{4}\textrm{He}+_{86}^{222}\textrm{Rn}$

To calculate the mass defect, we use the equation:

Mass defect = Sum of mass of product - Sum of mass of reactant

$\Delta m=(m_{Rn}+m_{He})-(m_{Ra})$

We know that:

$m_{Rn}=222.0176u\\m_{Ra}=226.0254u\\m_{He}=4.0026u$

Putting values in above equation, we get:

$\Delta m=(222.0176+4.0026)-(226.0254)=-0.0052g=-5.2\times 10^{-6}kg$

(Conversion factor: 1 kg = 1000 g )

To calculate the energy released, we use Einstein equation, which is:

$E=\Delta mc^2$

$E=(-5.2\times 10^{-6}kg)\times (3\times 10^8m/s)^2$

$E=-4.6800\times 10^{11}J$

Hence, the energy released in the decay process is $4.6800\times 10^{11}J$

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3 years ago

Why measurement standards are necessary

ivanzaharov [21]

Answer:

standard unit of measurement provides a reference point by which objects of weight, length or capacity can be described.

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4 years ago

Object A has of mass 7.20 kilograms, and object B has a mass of 5.75 kilograms. The two objects move along a straight line towar

Vera_Pavlovna [14]

If the collision is elastic, there is no loss in kinetic energies, which means that the total energies before and after impact are the same. So no need to worry about final velocities.

Final energy
= initial energy
= (1/2) (7.20*2.00^2+5.75*(-1.30)^2)
=19.26 joules

Answer: the total kinetic energy is 19.3 J. after collision.

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4 years ago

Electrons are continuously being knocked out of air molecules by cosmic ray particles from space. Once the electrons are free, t

nata0808 [166]

(a) $1.25\cdot 10^{-14} J$

The change in potential energy of the electron is given by:

$\Delta U=q E d$

where

$q=1.6\cdot 10^{-19}C$ is the magnitude of the electron's charge

$E=150 N/C$ is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

$\Delta U=(1.6\cdot 10^{-19}C)(150 N/C)(520 m)=1.25\cdot 10^{-14} J$

(b) 78 kV

The potential difference the electron has moved through is given by

$\Delta V=Ed$

where

$E=150 N/C$ is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

$\Delta V=Ed=(150 N/C)(520 m)=78,000 V=78 kV$

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3 years ago

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