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lubasha [3.4K]
3 years ago
10

Convert the following fraction to a decimal.

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0
I think it’s C but I could be wrong but I don’t think I am
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The fourth term of an arithmetic
yulyashka [42]

Answer:

2

Step-by-step explanation:

<u>Given AP where:</u>

  • a₄ = 2a₂ - 1
  • a₆ = 7

<u>To find</u>

  • a₁ = ?

<u>Since</u>

  • a₄ = a₁ + 3d
  • a₂ = a₁ + d
  • a₆ = a₁ + 5d

<u>Initial equations will change as:</u>

  • a₁ + 3d = 2(a₁ + d) - 1  ⇒  a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
  • a₁ + 5d = 7 ⇒ a₁ = 7 - 5d

<u>Comparing the above:</u>

  • d + 1 = 7 - 5d
  • 6d = 6
  • d = 1

<u>Then:</u>

  • a₁ = d + 1 = 1 + 1 = 2
  • a₁ = 2

The first term is 2

5 0
3 years ago
-5+5/3x=2 solve for x
LenaWriter [7]

Answer: 21/5

Step-by-step explanation:

6 0
3 years ago
Help only 12 minutes left middle school math
Alex_Xolod [135]

Answer:

C?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the equation of the line that is parallel to the given line and passes theought the point (12, -2)
Nesterboy [21]

Answer:

<u>Option </u><u>D</u> (y = 5/6x -12).

Step-by-step explanation:

Hey there!

The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].

According to the question, the first line passes through point (12,6) and (0,-4).

So,

slope(m1) =  \frac{y2 - y1}{x2 - x1}

or \: m1 =  \frac{ - 4 - 6}{0 - 12}

or \: m1 =   \frac{5}{6}

Therefore, the slope of the line is 5/6.

Now as per the condition of parallel lines, m1 =m2 = 5/6.

So, keeping the value of m2 in equation (i), we get;

(y+2) = 5/6(x-12)

y + 2 =  \frac{5}{6} x - 10

or, y = 5/6x - 12.

Therefore, the required equation is y = 5/6 X - 12.

<u>Hope</u><u> </u><u>it </u><u>helps</u><u>!</u>

3 0
3 years ago
Adam wrote a check for $38 to pay his monthly gas bill, but when balancing his checkbook, he accidentally recorded it as credit
andriy [413]

Answer: the balance in his check register will be $76 over the balance on his bank account

7 0
3 years ago
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