Answer:
pH of the H⁺(aq) is 0
Explanation:
It is possible to know the concentration of a HCl(aq) solution by titration with a solution of NaOH(aq) with known concentration. The reaction is:
HCl(aq) + NaOH(aq) → H₂O(l) + NaCl(aq)
The added moles of NaOH are equal to moles of HCl and as you know volume of HCl added you will obtain concentration of HCl.
Now, a solution of H⁺(aq) with a concentration 10 times greater than original NaOH(aq) solution -0.100M-, has a concentration of 1.00M H⁺(aq), the pH of this solution is:
pH = -log (1.00M H⁺(aq) = 0
That means <em>pH of the H⁺(aq) is 0</em>
M(NH₃)=51g, n(NH₃)=m/M=51g÷17g/mol(14+3×1)=3mol
N(NH₃)=n×Na(Avogadro number)=3mol×6·10²³1/mol=18×10²³ molecules
<span>Acid is a molecule capable of
donating hydrogen ion and they form aqueous solutions with a sour taste while
base is a substance that accepts proton from proton donor and in aqueous solution,
they have an astringent or bitter taste. Moreover, a good example for base is
sodium hydrogen carbonate as baking soda or baking powder and for acid, the
most common example is the acetic acid or vinegar.</span>
<span>
some elements have their outer electrons more tightly bound than
others. Those who have less tightly bound electrons are more reactive.
After this it gets more complex in explaining why they are bound with
different strengths. </span>
