Two commonly used units<span> to measure air pressure are Inches of Mercury and </span>Millibars.<span> </span>
Answer:
Explanation:
First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=
Answer:
v = 7.85 × 10¹⁴ Hz
Explanation:
The first three energy level can be represented as follows:
⇅ ------> n₄ = 4
⇅ ------> n₃ = 3
⇅ ------> n₂ = 0
ΔE = hv =
ΔE = hv =
ΔE = hv =
ΔE = hv =
where h = planck constant = J.s
mass (m) =
e = 0.904 nm =
hv =
hv =
hv =
hv = J
v =
v =
v =
v = 7.85 × 10¹⁴ Hz (since s⁻¹ is equivalent to 1 Hz)
Thus, the frequency of an electronic transition from the highest-occupied orbital to the lowest-unoccupied orbital = 7.85 × 10¹⁴ Hz