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kotykmax [81]
3 years ago
9

Why should impure zinc be used instead of pure zinc in preparation of hydrogen gas​

Chemistry
2 answers:
Yuri [45]3 years ago
5 0
Pure zinc is not used for the preparation of hydrogen gas because it is non-porous. As a result, the reaction carried out with pure zinc would be too slow. Hence impurities like copper is often added to the zinc. Copper acts as a catalyst ( by providing a large surface area ) and increases the speed of the reaction.
valina [46]3 years ago
3 0

Explanation:

Pure zinc is not used for preparation of hydrogen gas because it is non-porous. As a result, the reaction carried out with pure zinc would be too slow. Hence, impurities like copper is often added to the zinc. Copper acts as a catalyst and increases the speed of the reaction.

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Which of the following is the test for oxygen has?
dem82 [27]
A or B depends on what you mean by lit or glowing but when you place a wooden split in the sample the gas must reignite but there can be some confusion between hydrogen and oxygen mainly because a splint can cause a slight popping sound while it reignites but hydrogen pops are more violent and can most time extinguish the splint.
5 0
3 years ago
La masse et volume. S'il vous plaît repondre aux questions 2, 3, et 4.​
ella [17]

Answer:

Bonjour! Je me demandais si vous pouviez s’il vous plaît traduire vos questions en anglais afin que je puisse les résoudre. J’utilise un traducteur en ce moment pour vous dire votre réponse dans Français. Je suis désolé si vous ne pouvez pas traduire cela. Bonne journée!

Explanation:

3 0
3 years ago
Water is a polar molecule, meaning the electrons that are shared between the atoms aren't shared equally so oxygen attracts more
amm1812

Answer:

Magnet with a positive and a negative pole

Explanation:

A great analogy to demonstrate what a polar molecule looks like is to imagine a magnet. A magnet has one positively charged end and one negatively charged end, two poles, that is.

Imagine that we have a magnet of a shape of a prism (water molecule has a bent shape). The two base vertices of the face of the triangle are positively charged, that's because hydrogen is less electronegative than oxygen and, hence, the two hydrogen atoms are partially positively charged in a water molecule.

Oxygen is more electronegative than hydrogen meaning it has a greater electron-withdrawing force, so electrons are closer to oxygen within the O-H bonds. Oxygen, as a result, becomes partially negatively charged, so it's our negative pole of the magnet.

4 0
3 years ago
Select the correct answer. which substance in this redox reaction is the oxidizing agent? cu 2agno3 → 2ag cu(no3)2 a. n b. agno3
lana66690 [7]

AgNO₃ will act as the oxidising agent.

<h3><u>For the given chemical equation:</u></h3>

Cu + 2AgNO₃ →  2Ag + Cu(NO₃)₂

Half reactions for the given chemical reaction:

<u>Reducing agent:</u>

Cu → Cu²⁺ + 2e⁻

Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.

<u>Oxidising Agent</u>:

Ag⁺ + e⁻ → Ag

The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.

Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.

<h3><u>Oxidising and Reducing agents</u></h3>
  • An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
  • A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.

To know more about the process of Oxidation and Reduction, refer to:

brainly.com/question/4222605

#SPJ4

8 0
1 year ago
Need asap thank you
cupoosta [38]

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

6 0
2 years ago
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