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2 years ago

STOPPPP promising Brainliest if ur NOT GONNA GIVE IT.

Mathematics

2 answers:

Diano4ka-milaya [45]2 years ago

7 0

Answer:

i a free can I have brainliest

Anna35 [415]2 years ago

5 0

Answer:

Right I hate it when they do that!

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Am I dealing with harmonic stuff (trig)?

pochemuha

You just need to solve for when $y=0$ :

$\dfrac{\cos8t-9\sin8t}4=0\implies\cos8t-9\sin8t=0$

$\implies\cos8t=9\sin8t$

$\implies\dfrac19=\dfrac{\sin8t}{\cos8t}=\tan8t$

$\implies8t=\tan^{-1}\dfrac19+n\pi$

$\implies t=\dfrac18\tan^{-1}\dfrac19+\dfrac{n\pi}8$

where $n$ is any integer. We only care about when $0\le t\le1$ , which happens for $n\in\{0,1,2\}$ .

$t=\dfrac18\tan^{-1}\dfrac19\approx0.01$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi8\approx0.41$

$t=\dfrac18\tan^{-1}\dfrac19+\dfrac\pi4\approx0.80$

8 0

3 years ago

Pleaseeeeeee help mee

BlackZzzverrR [31]

Answer:

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

Step-by-step explanation:

Step(i):-

Given

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos( 3x - \frac{\pi }{3} ) = cos (\frac{\pi }{6} )$

$3x - \frac{\pi }{3} = \frac{\pi }{6}$

$3x - \frac{\pi }{3 } + \frac{\pi }{3} = \frac{\pi }{6} + \frac{\pi }{3}$

$3x = \frac{2\pi +\pi }{6} = \frac{3\pi }{6} = \frac{\pi }{2}$

$x = \frac{\pi }{6}$

Step(ii):-

The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

verification :-

$cos( 3x - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

put $x = \frac{\pi }{6}$

$cos( 3(\frac{\pi }{6}) - \frac{\pi }{3} ) = \frac{\sqrt{3} }{2}$

$cos (\frac{\pi }{6} ) = \frac{\sqrt{3} }{2} \\\\\frac{\sqrt{3} }{2} = \frac{\sqrt{3} }{2}$

Both are equal

∴The solution of the given trigonometric equation

$x = \frac{\pi }{6}$

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33% depending on if your numbers is the same as mine

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90 + 40h for Paul's Plumbing
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What are you trying to figure out? This is new to me XD

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I hope this helps!

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