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OleMash [197]
2 years ago
13

A boxer throws a punch with a force of 1,400 N that lasts 0.02 s. What is the impulse of this punch? (1 point) 28 kg⋅m/s 28 kilo

grams times meters per second 280 kg⋅m/s 280 kilograms times meters per second 70,000 kg⋅m/s 70,000 kilograms times meters per second 7,000 kg⋅m/s
Physics
1 answer:
Musya8 [376]2 years ago
7 0

The impulse of the boxers punch is 28 kgm/s.

The given parameters;

  • <em>applied force by the boxer, F = 1400 N</em>
  • <em>time of force action, t = 0.02 s</em>

<em />

The impulse of the boxers punch is calculated as follows;

J = Ft

where;

  • <em>F is the applied force (N)</em>
  • <em>t is the time of force action (s)</em>

The magnitude of the impulse is calculated as follows;

J = 1400 \times 0.02 \\\\J = 28 \ kg m/s

Thus, the impulse of the boxers punch is 28 kgm/s.

Learn more about impulse here: brainly.com/question/25700778

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