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sergejj [24]
2 years ago
8

Which of these terms is defined as the capacity to do work?

Physics
2 answers:
tresset_1 [31]2 years ago
7 0
Energy and work hope it helps
____ [38]2 years ago
4 0
" Energy " is the ability to do work.
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A student takes notes in class.
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The wrong statement is that sound waves created vibration Option A.

<h3>What are sound waves?</h3>

Sound is a type of waves that moves in compressions and rare factions. This implies that sound is a mechanical wave. Recall that a mechanical wave is one that requires a material medium for propagation. Now we know that if we set the medium into vibration, that is when the sound waves begins to vibrate. That brings us to the idea that it is the vibration that causes the sound waves and not the sound waves that creates the vibration.

Thus, knowing that sound is a mechanical wave which moves through solids liquids and gas and that the vibration of the source of sound is what causes the air to vibrate, we conclude that the wrong statement is that sound waves created vibration Option A.

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What process occurs when all of the energy from light waves is transferred to a medium?
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A solid plastic ball hits a stationary tennis ball in a perfectly elastic collision. If the mass of the plastic ball is three ti
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The two balls separate but continue to move in the same direction

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In an electric vehicle, each wheel is powered by its own motor. The vehicle weight is 4,000 lbs. By regenerative braking, its sp
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Answer:

the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh

Explanation:

Given that;

weight of vehicle = 4000 lbs

we know that 1 kg = 2.20462

so

m = 4000 / 2.20462 =  1814.37 kg

Initial velocity V_{i} = 60 mph = 26.8224 m/s

Final velocity V_{f} = 30 mph = 13.4112 m/s

now we determine change in kinetic energy

Δk = \frac{1}{2}m(  V_{i}² - V_{f}² )

we substitute

Δk = \frac{1}{2}×1814.37( (26.8224)² - (13.4112)² )

Δk = \frac{1}{2} × 1814.37 × 539.5808

Δk = 489500 Joules

we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule

so

Δk = 489500 / 3.6 × 10⁶

Δk = 0.13597 ≈ 0.136 kWh

Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh

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