In this question, you are given the gasoline density (0.749g/ml) and volume of the gasoline (19.2 gallons). You are asked the mass of the gasoline in pounds. Then you need to change the grams into pounds and the ml into gallons. The calculation would be:
mass of gasoline= density * volume
mass of gasoline= 0.749g/ml * (1 pound/453.592grams) * 3785.41ml/gallon * 19.2 gallon= 120 pounds
Answer:
<h3>Theanswer is 6 moles</h3>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>6 moles</h3>
Hope this helps you
Answer:
This unit has encouraged a deeper understanding of the world and it's guiding principles. While it was initially challenging for me to determine if a change was physical or chemical, this unit provided me with the information necessary to determine the type. With this knowledge, I can now interrelate with other properties and believe that this new ability will assist in future units as well. Thank you!
Explanation:
Answer:
The answer to your question is 0.5 moles
Explanation:
Data
moles of Glucose = ?
moles of carbon dioxide = 3
Balanced chemical reaction
6CO₂ + 6H₂O ⇒ C₆H₁₂O₆ + 6O₂
Process
To solve this problem, use proportions, and cross multiplication.
Use the coefficients of the balanced equation.
6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆
3 moles of CO₂ ---------------- x
x = (3 x 1) / 6
-Simplification
x = 3/6
-Result
x = 0.5 moles of Glucose
