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Leto [7]
2 years ago
12

What determines the role a tissue plays?​

Biology
1 answer:
Kisachek [45]2 years ago
8 0

Answer:

Humans—and other complex multicellular organisms—have systems of organs that work together, carrying out processes that keep us alive. ... Cells make up tissues, tissues make up organs, and organs make up organ systems. The function of an organ system depends on the integrated activity of its organs.

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Which of the three balls pictured below have gravitational potential energy.​
kumpel [21]

Answer:

i believe the basketball falling from the net

Explanation:

5 0
2 years ago
Why might scientists use computer models in research instead of conducting an experiment on the real system they would like to s
Usimov [2.4K]

Answer:

Using the real system might mess up and using a computer model is clearer and gives a more advanced view

3 0
3 years ago
QUICK!!!! HELP!!!!
pochemuha

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Millions of years ago, the Appalachians were taller than the Himalayas! Millions of years of erosion, however, have taken their toll. ... The crust that is now the Appalachians began folding over 300 million years ago, when the North American and African continental plates collided.

3 0
3 years ago
What factors improve soil fertility
Kruka [31]

here are majorly 12 factors influence Soil fertility

Infiltration of water.

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6 0
2 years ago
In guinea pigs hair straightness or curliness is thought to be governed by a single pair of alleles showing incomplete dominance
Nimfa-mama [501]

Answer:

Frequency of allele S is p = 0.4939

Frequency of allele C is q = 0.666

The population is not in Hardy-Weinberg equilibrium

Explanation:

Given -

Number of individuals with straight hair = 244

Number of individuals with curly hair = 444

Number of individuals with Wavy hair = 312

Let "p" represents the frequency for allele for straight hair and "q" represents the frequency for allele for curly hair

p^2 represents the frequency of genotype "SS"

p^{2} = \frac{244}{1000} \\= 0.244

q^2 represents the frequency of genotype "CC"

p^{2} = \frac{444}{1000} \\= 0.444

2pq represents the frequency of genotype "SC"

2pq = \frac{312}{1000} \\= 0.312

Frequency of allele S is p

= \sqrt{0.244} \\= 0.4939

Frequency of allele C is q

tex]= \sqrt{0.444} \\= 0.666[/tex]

For being in Hardy Weinberg's equation-

p+q=1\\

Substituting the values in above equation, we get -

0.4939+0.666\neq 1

hence, the population is not in Hardy-Weinberg equilibrium

4 0
3 years ago
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