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VARVARA [1.3K]
3 years ago
15

How fast an object is moving is its

Physics
1 answer:
faltersainse [42]3 years ago
4 0

Answer:

D. Speed !!!!!

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What happens to mechanical energy if the potential energy of an object decreases?
OleMash [197]

D. Mechanical energy remains unchanged.

Mechanical energy = Potential energy + Kinetic energy

So if potential energy decreases, then kinetic energy must increase so that the system is balanced.

6 0
3 years ago
As a moon follows its orbit around a planet, the maximum grav- itational force exerted on the moon by the planet exceeds the min
Mars2501 [29]
The gravitational force exerted on the moon by the planet when the moon is at maximum distance r_{max} is
F_{min}=G \frac{Mm}{r_{max}^2}
where G is the gravitational constant, M and m are the planet and moon masses, respectively. This is the minimum force, because the planet and the moon are at maximum distance.

Similary, the gravitational force at minimum distance is
F_{max}=G \frac{Mm}{r_{min}^2}
And this is the maximum force, since the distance between planet and moon is minimum.

The problem says that F_{max} exceeds F_{min} by 11%. We can rewrite this as
F_{max}=(1+0.11)F_{min}=1.11 F_{min}

Substituing the formulas of Fmin and Fmax, this equation translates into
\frac{1}{r_{min}^2}=1.11  \frac{1}{r_{max}^2}
and so, the ratio between the maximum and the minimum distance is
\frac{r_{max}}{r_{min}}= \sqrt{ 1.11 }=1.05
8 0
4 years ago
A gull is flying horizontally 10.80 m above the ground at 6.00 m/s. The bird is carrying a clam in its beak and plans to crack t
UkoKoshka [18]

Answer:

v_y = 14.55 m/s

Explanation:

given,

height at which gull is flying = 10.80 m

speed of the gull = 6 m/s

acceleration due to gravity = 9.8 m/s²

Relative to the seagull, the x-speed is 0,

because the seagull has the same x-speed.

Only the y-speed counts:

v_y^2 = u^2 + 2 g h

v_y^2 = 0^2 + 2 g h

v_y = \sqrt{2gh}

v_y = \sqrt(2\times 9.8 \times 10.8)  

v_y = \sqrt(211.68)

v_y = 14.55 m/s

hence, the speed at which the clam smash the rock is v_y = 14.55 m/s

8 0
3 years ago
What is the density of a rock that has a mass of 454g and volume of 100.0cm
Mademuasel [1]

Answer:

4.54 g/cm3

Explanation:

7 0
3 years ago
A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically dr
yan [13]

Answer:

49.79 m/s

Explanation:

Given:

Initial velocity of the roller coaster is, u=0\ m/s

Vertical drop or the displacement of the roller coaster is, y=-126.5\ m

The displacement is negative as the motion is in downward direction.

Now, as the motion is in vertical direction only, the acceleration of the roller coaster will be due to gravity acting in the downward direction.

So, the acceleration of the roller coaster is, a=g=-9.8\ m/s^2

Now, using the following equation of motion:

v^2=u^2+2ay

Where, 'v' is the velocity of the roller coaster at the bottom.

Plug in all the given values and solve for 'v'. This gives,

v^2=0^2+2(-9.8)(-126.5)\\\\v^2=2479.4\\\\v=\sqrt{2479.4}\\\\v=49.79\ m/s

Therefore, the speed of the roller coaster at the bottom of the drop is 49.79 m/s.

7 0
3 years ago
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