Answer:
According to the standard Safe Practices for Motor Vehicle Operations, ANSI/ASSE Z15.1, defensive driving skills involves "driving to save lives, time, and money, in spite of the conditions around you and the actions of others."
Explanation:
Defensive driving is a type of training provided to the learners eligible to drive motor vehicles. It involves the basics of driving and rules involved in driving. The learners learn about the methods of driving safely with the minimum expense of time and money. It also helps in reducing the risks of collision in adverse situations. The methods to rescue oneself from dangerous situations are also trained. Preventing oneself from the mistakes of others is also termed under defensive driving.
Answer:
Fire/Flame resistant clothing and aprons
Explanation:
Individuals working with or around welding equipment are usually required to wear Fire/Flame resistant clothing and aprons which are designed to protect the user from various types of hazards including heat, fires
, burns
, and sometimes radiation. In this scenario, it would protect the individual from the welding sparks that are produced when welding, which tends to fly all over the place and can catch fire in some cases. These clothes will prevent that from happening.
Answer:
74.12kg/day
Explanation:
Equation of reaction for the neutralization reaction of sodium hydroxide and sulfuric acid: 2NaOH + H2SO4 yields Na2SO4 + 2H2O
Mass of sulfuric acid produced per day = 90,800kg
Percentage of sulfuric acid in wastewater = 0.1%
Mass of sulfuric acid that ends up in wastewater per day = 0.1/100 × 90,800 = 90.8kg
From the equation of reaction, 2 moles of NaOH (80kg of NaOH) is required to neutralize 1 mole of H2SO4 (98kg of H2SO4)
80kg of NaOH is required to neutralize 98kg of sulfuric acid
90.8kg of sulfuric acid would be neutralized by (90.8×80)/98kg of NaOH = 74.14kg/day of NaOH
Answer:
for m1=0.2
M2=0.4
for m1=2.5
M2=5
1= channel input
2.channel output
Explanation:
Hello!
To solve this problem follow the steps below!
1.As it is an isentropic system, it means that the temperature of the fluid remains constant, so the volumetric flow is the same, remember that this is calculated by calculating the product between the velocity and the area.
V1A1=V2A2
1= channel input
2.channel output
We can divide both sides of the equation by the speed of sound(V)
2. The mach number is defined as the ratio between the speed of a fluid and the speed of sound,
we rearrange the equation
M1A1=M2A2
3.Now considering that the channel is convergent and that the ratio between the areas is 2, we have the following equation (A1 / A2 = 2)
M1(2)=M2
4.Finally we solve for the number of mach indicated (0.2 and 2.5)
for m1=0.2
0.2(2)=M2=0.4
for m1=2.5
2.5(2)=M2=5
Answer:
23.34 seconds
Explanation:
Flow rate = 1500
Arrival = 800 vehicle per hour
Cycle c = 60 seconds
Dissipation time = 10 seconds
Arrival time = 800/3600 = 0.2222
Rate of departure = 1500/3600 = 0.4167
Traffic density p = 0.2222/0.4167 = 0.5332
Real time = r
r + to + 10 = c
to = c-r-10 ----1
t0 = p*r/1-p ----2
Equate both 1 and 2
C-r-10 = p*r/1-p
60-r-10 = 0.5332r/1-0.5332
50-r = 0.5332r/0.4668
50-r = 1.1422r
50 = 1.1422r + r
50 = 2.1422r
r = 50/2.1422
r = 23.34 seconds
