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3 years ago

1. Defensive driving involves?

Engineering

1 answer:

-Dominant- [34]3 years ago

4 0

Answer:

According to the standard Safe Practices for Motor Vehicle Operations, ANSI/ASSE Z15.1, defensive driving skills involves "driving to save lives, time, and money, in spite of the conditions around you and the actions of others."

Explanation:

Defensive driving is a type of training provided to the learners eligible to drive motor vehicles. It involves the basics of driving and rules involved in driving. The learners learn about the methods of driving safely with the minimum expense of time and money. It also helps in reducing the risks of collision in adverse situations. The methods to rescue oneself from dangerous situations are also trained. Preventing oneself from the mistakes of others is also termed under defensive driving.

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State two main consumers of electricity transmitted at low frequency Calculate the primary voltage of a transformer if the prima

bagirrra123 [75]

Answer:

1) a. Customers requiring AC electric power transmission for powering remote devices which may include a subsea transmission system where power is distributed to subsea devices

b. Customers that utilize commutator-type motors

2) The primary voltage is 150 volts

Explanation:

The parameters given are;

Number of primary winding, $N_p$ = 50 turns

Number of secondary winding, $N_s$ = 150 turns

Voltage in secondary winding, $V_s$ = 450 volts

Voltage in primary winding = $V_p$

The relation between $N_p$ , $N_s$ , $V_s$ and $V_p$ is as follows;

$\dfrac{V_p}{V_s} = \dfrac{N_p}{N_s}$

Which gives;

$V_p = \dfrac{N_p \times V_s}{N_s}$

From which we have;

$V_p = \dfrac{50\times 450}{150} = 150 \ volts$

The primary voltage = 150 volts.

7 0

4 years ago

Read 2 more answers

A floor system has W24 x 55 sections spaced 8’-0"" o.c. supporting a floor dead load of 50 psf and a live load of 80 psf. Determ

galben [10]

Answer:

Load sup[port by beam is 1040 lb/ft

Explanation:

Given data:

dead load of floor is 50 psf

live load of floor is 80 psf

load per meter can be determined as

Load/mt length = load intensity × effective width

total load = deal load + live load

= 50 + 80 = 130 psf

load /mt length = 130 × 8

= 1040 p/ft = 1.04 k /ft

hence load sup[port by beam is 1040 lb/ft

4 0

4 years ago

First drilled to a depth of 1 47/64 how much deeper must it be drilled to reach the depth indicated?

lara [203]

Answer:

1 13/64

Explanation:

The depth of the hole is the height of the block less the remaining material below the hole:

depth = 1 3/8 +1 15/16 - 3/8 = (1 3/8 -3/8) +1 15/16 = 2 15/16

We want to find the difference between this depth and the depth of the hole already drilled:

2 15/16 -1 47/64 = 2 60/64 -1 47/64

= (2 -1) +(60 -47)/64 = 1 13/64

The hole must be drilled 1 13/64 deeper to match the drawing.

7 0

2 years ago

You are hitting a nail with a hammer (mass of hammer =1.8lb) the initial velocity of the hammer is 50 mph (73.33 ft/sec). The ti

Archy [21]

Answer:

The nail exerts a force of 573.88 Pounds on the Hammer in positive j direction.

Explanation:

Since we know that the force is the rate at which the momentum of an object changes.

Mathematically $\overrightarrow{F}=\frac{\Delta \overrightarrow{p}}{\Delta t}$

The momentum of any body is defines as $\overrightarrow{p}=mass\times \overrightarrow{v}$

In the above problem we see that the moumentum of the hammer is reduced to zero in 0.023 seconds thus the force on the hammer is calculated using the above relations as

$\overrightarrow{F}=\frac{m(\overrightarrow{v_{f}}-\overrightarrow{v_{i}})}{\Delta t}$

$\overrightarrow{F}=\frac{m(0-(-73.33)}{0.23}=\frac{1.8\times 73.33}{0.23}=573.88Pounds$

6 0

3 years ago

A long cylindrical black surface fuel rod of diameter 25 mm is shielded by a surface concentric to the rod. The shield has diame

Elden [556K]

Answer:

surface temp of fuel rod = 678.85 K

Explanation:

Given data :

D1 = 25 mm

D2 = 50 mm

T2 = 335 k

T∞ = 300 k

hconv = 0.15 w/m^2.k

ε2 = 0.05

ε1 = 1

Determine energy at Q23

Q23 = Qconv + Qrad

attached below is the detailed solution

Insert given values into equation 1 attached below to obtain the surface temperature of the fuel rod ( T1 )

4 0

3 years ago