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2 years ago

Identify the labeled structures, A B C D E A Btw this is science so ye-

Chemistry

1 answer:

mestny [16]2 years ago

6 0

Answer:

A Golgi body

B vacuole

C mitochondrion

D nucleus

E cell membrane

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murzikaleks [220]

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Explanation:

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3 years ago

A drink is made up mostly of water. A small amount of sweet powder is stirred in using a spoon. The power in this solution is th

Helen [10]

Well the solvent is the liquid in a solution so your answer would be Solute, D. That is the one that would represent the sugar crystals being evenly mixed into a solution.

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3 years ago

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A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from

sweet-ann [11.9K]

Answer:

$T_i~=163.1$ ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

Initial temperature of gold= Unknow

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the heat equation:

$Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT$

$Q_A_u=m_A_u*Cp_A_u*deltaT$

We can relate these equations if we take into account that all heat of gold is transfer to the water, so:

$m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT$

Now we can put the values into the equation:

$60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)$

Now we can solve for the initial temperature of gold, so:

$T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20$

$T_i~=163.1$ ºC

I hope it helps!

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3 years ago

How does the total volume of gas particles compare to the volume of the space between gas particles?

saw5 [17]

Answer:
There is more space between gas particles than the size of the particles.

Explanation:
This scenario can be understand by taking a very simple example. As we know that 1 mole of any gas at standard temperature and pressure occupy 22.4 liters of volume. Lets take Hydrogen gas and Oxygen gas, 1 mole of each gas will occupy same volume. Why it is so? Why same volume although Oxygen is 16 times more heavier? This is because the space between gas molecules is very large. Approximately the distance between gas molecules is 300 times greater than their own diameter from its neighbor molecules.

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4 years ago

Thermal Energy Transfer Lab Edge 2021 help please

lutik1710 [3]

Answer:

i dont know?

Explanation:

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3 years ago

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