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nadya68 [22]
2 years ago
13

I wonder if people that say that there ugly is to get attention (not to be mean...)​

Physics
2 answers:
Alexeev081 [22]2 years ago
7 0
They do they want love bc their parents didn’t
alexandr1967 [171]2 years ago
5 0
They do. mostly because they want validation from others
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Name the four major forces in the universe that act over long distance as I greater than the nucleus of an atom?
GalinKa [24]
Forces in the universe that act over long distance, meaning the distance is greater than the diameter of the nucleus of the atom are:

1. Electrostatic force or Coulomb force: Fc=(k*Q₁*Q₂)/r²,

2. Gravitational force: Fg=(G*m₁*m₂)/r²,

3. Magnetic force: Fm=qvB,

4. London dispersion force, also known as one of the van der Waals forces. 
4 0
3 years ago
Even if all stars were the same distance from Earth, their absolute magnitude and
k0ka [10]

Answer: True


hope this helps!

4 0
2 years ago
What is the definition of density?​
Luba_88 [7]

Answer:

Density is the amount of mass in a specified space. It is a way to measure how compact an object is

Explanation:

6 0
3 years ago
Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of
STatiana [176]

Answer:

2.27\cdot 10^{49}

Explanation:

The gravitational force between the proton and the electron is given by

F_G=G\frac{m_p m_e}{r^2}

where

G is the gravitational constant

m_p is the proton mass

m_e is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N

The electrical force between the proton and the electron is given by

F_E=k\frac{q_p q_e}{r^2}

where

k is the Coulomb constant

q_p = q_e = q is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N

So, the ratio of the electrical force to the gravitational force is

\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}

So, we see that the electrical force is much larger than the gravitational force.

5 0
3 years ago
When two equal forces act on the same object in opposite directions, what is the net force?
sertanlavr [38]

Answer:

0

Explanation:

Forces with equal magnitudes and opposite directions cancel each other out, so the net force is 0.

6 0
3 years ago
Read 2 more answers
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